python - 在 Python 中使用 os.walk 查找大于 300MB 的文件？

Question

我编写此代码是为了遍历目录并查找大于 300MB 的文件。

但是，我得到了很多重复值，并且文件之间的重复值数量各不相同。谁能解释一下或者为我改进代码？

import os

path = 'C:\\Users\\brentond\\Desktop\\Lower Thames Crossing'
for foldername, subfolders, filenames in os.walk(path):
    for subfolder in subfolders:
        for filename in filenames:
            if os.path.getsize(os.path.join(foldername, filename))>300000000:
                print(foldername + '\\' + filename)

Answer 1

您不必自己探索子文件夹，walk为你做。

来自文档:

os.walk(top, topdown=True, onerror=None, followlinks=False)

Generate the file names in a directory tree by walking the tree either top-down or bottom-up. For each directory in the tree rooted at directory top (including top itself), it yields a 3-tuple (dirpath, dirnames, filenames).

(强调我的)

所以，只需这样做:

import os

path = 'C:\\Users\\brentond\\Desktop\\Lower Thames Crossing'
for foldername, subfolders, filenames in os.walk(path):
    for filename in filenames:
        if os.path.getsize(os.path.join(foldername, filename))>300000000:
            print(foldername + '\\' + filename)