我有一个发票对象列表,其属性为频率和金额(BigDecimal)。
1)需要根据频率相乘并更改数量,而不会失去精度。在下面显示的代码中尝试过,但输出失去了一些精度。金额值应为 100。
2) 是否可以使用 java 8 流 API 替换发票列表中的金额值。 尝试使用
invoiceList.forEach(s -> s.getAmount().multiply(new BigDecimal("10")));
但这不会替换对象中的金额值。 在这种情况下无法弄清楚使用replaceAll,尝试了下面的代码但给出了编译错误,
newList.replaceAll((v) -> v.getAmount().multiply(frequencyFactor.get(v.getFrequency())));
整个主类如下。无法更改任何数据类型或设计。我必须处理从网络服务获取的列表。
public class InvoiceMain {
public static void main(String[] args) {
List<Invoice> invoiceList = Arrays.asList(new Invoice("Quarterly", new BigDecimal(300)), new Invoice("Annually", new BigDecimal(1200)));
Map<String, BigDecimal> frequencyFactor = new HashMap<>();
frequencyFactor.put("Annually", new BigDecimal(1.0 / 12));
frequencyFactor.put("Quarterly", new BigDecimal(1.0 / 3));
for (Invoice invoice : invoiceList) {
invoice.setAmount(invoice.getAmount().multiply(frequencyFactor.get(invoice.getFrequency())));
}
System.out.println(invoiceList);
}
}
class Invoice {
private String frequency;
private BigDecimal amount;
public Invoice(String frequency, BigDecimal amount) {
super();
this.frequency = frequency;
this.amount = amount;
}
public String getFrequency() {
return frequency;
}
public void setFrequency(String frequency) {
this.frequency = frequency;
}
public BigDecimal getAmount() {
return amount;
}
public void setAmount(BigDecimal amount) {
this.amount = amount;
}
@Override
public String toString() {
return "Invoice [frequency=" + frequency + ", amount=" + amount + "]";
}
}
输出是:
[Invoice [frequency=Quarterly, amount=99.999..], Invoice [frequency=Annually, amount=99.999...]]
所需的输出是
[Invoice [frequency=Quarterly, amount=100], Invoice [frequency=Annually, amount=100]]
最佳答案
该缺陷是将 BigDecimal 构造函数与 double 一起使用。然后 BigDecimal 无法确定精度并使用适合 double 的精度,同时引入了不精确的值(来自 double )。
new BigDecimal(1.0/12)
最好改为随后除以 12:使用 divideBy
。
Map<String, BigDecimal> divisors = ...
divisors.put("Anually", BigDecimal.valueOf(12));
...
final Map<String, BigDecimal> finalDivisors = divisors;
BigDecimal sum = invoiceList.stream()
.map(inv -> inv.amount.divideBy(finalDivisors.get(inv.frequency))
.sum();
<小时/>
在实际代码中:
static class Invoice {
final BigDecimal amount;
final int months;
Invoice(BigDecimal amount, int months) {
this.amount = amount;
this.months = months;
}
}
public static void main(String[] args) {
List<Invoice> invoices = Arrays.asList(
new Invoice(new BigDecimal("12.50"), 3),
new Invoice(new BigDecimal("120.50"), 12),
new Invoice(new BigDecimal("7.25"), 3));
BigDecimal sum = invoices.stream()
.map(inv -> inv.amount.divide(BigDecimal.valueOf(inv.months),
RoundingMode.HALF_UP))
.reduce(BigDecimal.ZERO, BigDecimal::add);
System.out.println("Sum: " + sum); // 16.63
}
关于java - 使用java 8除对象列表中的bigdecimal值?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/44144968/