如标题所示,我想使用 Python 将圆柱体拟合到一组 3D 点。这是一个不错的solution with MATLAB 。我们如何用Python 来做到这一点?
最佳答案
使用 scipy.optimize.leastsq,我们可以创建一个误差函数,其中观察到的圆柱体半径与建模半径之间的差异最小化。下面是拟合立式圆柱体的示例
import numpy as np
from scipy.optimize import leastsq
def cylinderFitting(xyz,p,th):
"""
This is a fitting for a vertical cylinder fitting
Reference:
http://www.int-arch-photogramm-remote-sens-spatial-inf-sci.net/XXXIX-B5/169/2012/isprsarchives-XXXIX-B5-169-2012.pdf
xyz is a matrix contain at least 5 rows, and each row stores x y z of a cylindrical surface
p is initial values of the parameter;
p[0] = Xc, x coordinate of the cylinder centre
P[1] = Yc, y coordinate of the cylinder centre
P[2] = alpha, rotation angle (radian) about the x-axis
P[3] = beta, rotation angle (radian) about the y-axis
P[4] = r, radius of the cylinder
th, threshold for the convergence of the least squares
"""
x = xyz[:,0]
y = xyz[:,1]
z = xyz[:,2]
fitfunc = lambda p, x, y, z: (- np.cos(p[3])*(p[0] - x) - z*np.cos(p[2])*np.sin(p[3]) - np.sin(p[2])*np.sin(p[3])*(p[1] - y))**2 + (z*np.sin(p[2]) - np.cos(p[2])*(p[1] - y))**2 #fit function
errfunc = lambda p, x, y, z: fitfunc(p, x, y, z) - p[4]**2 #error function
est_p , success = leastsq(errfunc, p, args=(x, y, z), maxfev=1000)
return est_p
if __name__=="__main__":
np.set_printoptions(suppress=True)
xyz = np.loadtxt('cylinder11.xyz')
#print xyz
print "Initial Parameters: "
p = np.array([-13.79,-8.45,0,0,0.3])
print p
print " "
print "Performing Cylinder Fitting ... "
est_p = cylinderFitting(xyz,p,0.00001)
print "Fitting Done!"
print " "
print "Estimated Parameters: "
print est_p
关于python - 将圆柱体拟合到分散的 3D XYZ 点数据,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/43784618/