sql - 如何从出生日期计算年龄(年.月格式)

Question

我写了一个查询，但它只返回几年，但我也需要几个月。以下是我编写的查询:

select cast(datediff(DAY, '2000-06-01 10:00:01', getDate() -1) / (365.23076923074) as varchar) as 'Age'

Answer 1

试试这个:

declare @DateOfBirth date= '1999-06-1'

Select AgeYears=DATEDIFF(year,@DateOfBirth ,getdate())- CASE WHEN MONTH(getdate())*100+DAY(getdate())<MONTH(@DateOfBirth)*100+DAY(@DateOfBirth) then 1 else 0 end
    ,AgeMoanths=(DATEDIFF(month,@DateOfBirth,getdate())  - CASE WHEN DAY(getdate())<DAY(@DateOfBirth) THEN 1 ELSE 0 END ) % 12
    ,Agedays=DATEDIFF (day,dateadd(month,(DATEDIFF(month,@DateOfBirth,getdate())  - CASE WHEN DAY(getdate())<DAY(@DateOfBirth) THEN 1 ELSE 0 END )  ,@DateOfBirth) ,getdate())