Fabric 2.0.1 运行调用 fabfile.py 的项目时出错。我使用的是 Python 3.5.1。有谁知道为什么会发生这种情况吗?
Traceback (most recent call last):
File ".bootstrap/_pex/pex.py", line 367, in execute
File ".bootstrap/_pex/pex.py", line 293, in _wrap_coverage
File ".bootstrap/_pex/pex.py", line 325, in _wrap_profiling
File ".bootstrap/_pex/pex.py", line 410, in _execute
File ".bootstrap/_pex/pex.py", line 468, in execute_entry
File ".bootstrap/_pex/pex.py", line 486, in execute_pkg_resources
File "/root/.pex/install/invoke-1.0.0-py3-none-any.whl.a7f464a6969cebbbd25df555b795379694067bba/invoke-1.0.0-py3-none-any.whl/invoke/program.py", line 321, in run
self.parse_collection()
File "/root/.pex/install/invoke-1.0.0-py3-none-any.whl.a7f464a6969cebbbd25df555b795379694067bba/invoke-1.0.0-py3-none-any.whl/invoke/program.py", line 399, in parse_collection
self.load_collection()
File "/root/.pex/install/fabric-2.0.1-py2.py3-none-any.whl.ae5e123ea5423bf8dce5f39ab3d9b0b8eb7b8e39/fabric-2.0.1-py2.py3-none-any.whl/fabric/main.py", line 74, in load_collection
super(Fab, self).load_collection()
File "/root/.pex/install/invoke-1.0.0-py3-none-any.whl.a7f464a6969cebbbd25df555b795379694067bba/invoke-1.0.0-py3-none-any.whl/invoke/program.py", line 588, in load_collection
module, parent = loader.load(coll_name)
File "/root/.pex/install/invoke-1.0.0-py3-none-any.whl.a7f464a6969cebbbd25df555b795379694067bba/invoke-1.0.0-py3-none-any.whl/invoke/loader.py", line 75, in load
module = imp.load_module(name, fd, path, desc)
File "/usr/local/lib/python3.5/imp.py", line 234, in load_module
return load_source(name, filename, file)
File "/usr/local/lib/python3.5/imp.py", line 172, in load_source
module = _load(spec)
File "<frozen importlib._bootstrap>", line 693, in _load
File "<frozen importlib._bootstrap>", line 673, in _load_unlocked
File "<frozen importlib._bootstrap_external>", line 662, in exec_module
File "<frozen importlib._bootstrap>", line 222, in _call_with_frames_removed
File "/etc/appliance/fabric/fabfile.py", line 1, in <module>
from fabric.contrib import *
ImportError: No module named 'fabric.contrib'
最佳答案
在 Fabric 2.0 中,contrib
模块不再存在。模块已被 Python 类取代,并且 contrib
模块已分布在这些类中。
您可以查看新的代码库 on github .
关于python - 导入错误:没有名为 'fabric.contrib' 的模块,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/50418536/