matlab - 如何在矩阵的最后一列中移零

Question

我有一个如下所示的矩阵-

A=[1 1 1 1 1;
   0 1 1 1 2;
   0 0 1 1 3]

但是我想将所有 0 放在行的末尾，所以 A 应该像 -

A=[1 1 1 1 1;
   1 1 1 2 0;
   1 1 3 0 0] 

我该怎么做？请Matlab专家帮助我。

Answer 1

给你。整个矩阵，无循环，甚至适用于非连续零:

A = [1 1 1 1 1; 0 1 1 1 2; 0 0 1 1 3];

At = A.'; %// It's easier to work with the transpose
[~, rows] = sort(At~=0,'descend'); %// This is the important part.
%// It sends the zeros to the end of each column
cols = repmat(1:size(At,2),size(At,1),1);
ind = sub2ind(size(At),rows(:),cols(:));
sol = repmat(NaN,size(At,1),size(At,2));
sol(:) = At(ind);
sol = sol.'; %'// undo transpose

与往常一样，对于在函数返回时不支持 ~ 符号的 Matlab 版本，请将 ~ 更改为虚拟变量，例如:

[nada, rows] = sort(At~=0,'descend'); %// This is the important part.