我正在从两个文件中获取电影项目,并通过使用扫描仪读取文件内容将这两个内容添加到数组列表“listOne”和“listTwo”中。然后将这两个列表合并为一个。然而,虽然扫描仪可以很好地读取文件,但我的 .add 似乎没有将它们正确添加到 ArrayLists 中。
我确保我的合并器和打印器都能正常工作。完成此操作后,我打印了扫描仪正在读取的内容以及添加后列表的内容。扫描仪显示正确的信息(即 A,J.Edgar,2011,R,1),但列表内容为我提供了基本值(即 [标题:,年份:0,评级:null,评论:0;] )。
//这是我的主类
Scanner fileScanner; //Scanner to read TestInput1.txt
Scanner fileScannerTwo; //Scanner to read TestInput2.txt
ArrayList<Movie>listOne = new ArrayList<Movie>(); //first list
ArrayList<Movie>listTwo = new ArrayList<Movie>(); //second list
ArraryList<Movie>outList = new ArrayList<Movie>(); //merged&sorted list
try{
fileScanner = GetInputFile("Enter input filename: ");
while(fileScanner.hasNextLine())
{
String[] elements = fileScanner.nextLine().split(",");
if(elements[0].equals("A")) //each movie has "A" to give ok
{
listOne.add(new Movie(elements[1],
Integer.parseInt(elements[2]), elements[3],
Integer.parseInt(elements[4])));
}
}
//The same code but replace "listOne" with "listTwo"
..........
..........
//PrintWriter that works properly
..........
..........
}//end of try
catch(FileNotFoundException ex){
System.out.println("User terminated program");
}
''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''' '
//this is my Movie class
private String movieTitle;
private int releaseYear;
private String rating;
private int movieReview;
public Movie(String Title, int Year, String rating, int Review)
{
movieTitle = "";
releaseYear = 0;
rating = "";
movieReview = 0;
}
public String getTitle()
{
return movieTitle;
}
public int getYear()
{
return releaseYear;
}
public String getRating()
//same stuff
public int getReview()
//same stuff
public int compareTo(Movie other) //haven't used this yet, but will to sort
{
int makeComparison = this.movieTitle.compareTo(other.movieTitle);
if(makeComparison != 0)
return makeComparison;
else
{
if(this.releaseYear != other.releaseYear)
return this.releaseYear - other.releaseYear;
else
return 0;
}
}
public String toString()
{
return String.format("Title: %s, Year: %s, Rating: %s, Review: %s;",
this.movieTitle, this.releaseYear, this.rating,
this.movieReview);
}
我希望输出看起来像 [标题:J.Edgar,年份:2011,评级:R,评论:1] 但我得到 [标题:,年份:0,评级:空,评论:0;]
以下是该文件的示例: A、J。埃德加,2011,R,1
A,夺宝奇兵与末日神殿,1984,PG,1
A,母亲节,2016,PG-13,4
A,世界史第一部分,1981,R,1
A,鳄鱼猎人,2002,PG,2
最佳答案
发现问题:
public Movie(String Title, int Year, String rating, int Review)
{
movieTitle = "";
releaseYear = 0;
rating = "";
movieReview = 0;
}
您没有使用任何构造函数参数。您只是总是将标题设置为“”,将发行年份设置为 0 等等。
试试这个:
public Movie(String Title, int Year, String rating, int Review)
{
movieTitle = Title;
releaseYear = Year;
this.rating = rating;
movieReview = Review;
}
此外,请考虑遵循 Java 命名和代码标准。普遍接受的标准是变量名始终以小写字母开头,而编写构造函数就是使用与类成员完全相同的名称,因此:
public Movie(String movieTitle, int releaseYear, String rating, int movieReview) {
this.movieTitle = movieTitle;
this.releaseYear = releaseYear;
this.rating = rating;
this.movieReview = movieReview;
}
关于java - 如何使用扫描仪将项目添加到数组列表,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/55837512/