我有一段使用传统 for 循环编写的工作代码,如下所示。我想重构它以使用 java 8 流并删除 for 循环。下面代码的输出应该是 3,因为这是最长的连续数字列表(4、5 和 6)
List<Integer> weekDays = Lists.newArrayList(1, 2, 4, 5, 6);
List<Integer> consecutiveIntervals = Lists.newArrayList();
int maxConsecutiveTillNow = 1;
for (int i = 1; i < weekDays.size(); i++) {
if (weekDays.get(i) - weekDays.get(i - 1) == 1) {
maxConsecutiveTillNow++;
} else {
consecutiveIntervals.add(maxConsecutiveTillNow);
maxConsecutiveTillNow = 1;
}
}
consecutiveIntervals.add(maxConsecutiveTillNow);
System.out.println(consecutiveIntervals.stream()
.max(Integer::compareTo)
.get()
);
最佳答案
Stream
API 不太适合此类问题。几乎不可能以正确的方式跟踪 Stream
中可见的元素。所以你必须选择多个Streams
。
基于 Stuart Marks' 之一答案。
List<Integer> weekDays = Arrays.asList(1, 2, 4, 5, 6);
int[] indices = IntStream.rangeClosed(0, weekDays.size())
.filter(i -> i == 0 || i == weekDays.size() || weekDays.get(i - 1) + 1 != weekDays.get(i))
.toArray();
int longest = IntStream.range(0, indices.length - 1).map(i -> indices[i + 1] - indices[i])
.max().orElseThrow(NoSuchElementException::new);
System.out.println(longest);
输出
3
关于java - 使用java 8流在排序数字列表中查找最长的连续数字,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41344690/