我正在尝试从 mongoDb 获取时间表数据。 我创建了适当的聚合并尝试在 Spring 框架内转换它。
db.theaters.aggregate([
{ $match: { 'city_id': <someCityId>, 'theatreRooms.schedules.spectacle_id': <someSpecId> } },
{ $unwind: '$theatreRooms' },
{ $unwind: '$theatreRooms.schedules' },
{ $group: { _id: { name: '$name', room: '$theatreRooms.name' }, schedules: { $addToSet: '$theatreRooms.schedules.time' } } },
{ $group: { _id: '$_id.name', schedules: { $addToSet: { room: '$_id.room', schedules: '$schedules' } } } }
])
我已经创建了正确的匹配和展开操作。但我在第一组操作时遇到了问题。 看来该操作得到了很好的解释,但由于某种原因我无法正确映射 _id 对象。
这是我的代码示例:
public class TheaterProject {
private TheaterId _id;
private List<String> schedules;
public TheaterId get_id() {
return _id;
}
public void set_id(TheaterId _id) {
this._id = _id;
}
public List<String> getSchedules() {
return schedules;
}
public void setSchedules(List<String> schedules) {
this.schedules = schedules;
}
}
public class TheaterId {
@Field("name")
private String name;
@Field("room")
private Integer room;
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public Integer getRoom() {
return room;
}
public void setRoom(Integer room) {
this.room = room;
}
}
public Document getRawSchedules(String cityId, String spectaclesId){
MatchOperation match = Aggregation.match(Criteria.where("city_id").is(cityId).and("theatreRooms.schedules.spectacle_id").is(spectaclesId));
UnwindOperation theaterUnwind = Aggregation.unwind("theatreRooms");
UnwindOperation schedulesUnwind = Aggregation.unwind("theatreRooms.schedules");
GroupOperation firstGroup = Aggregation.group(Fields.from(
Fields.field("name", "name"),
Fields.field("room", "theatreRooms.name")))
.addToSet("theatreRooms.schedules.time").as("schedules");
Aggregation agg = Aggregation.newAggregation(match,theaterUnwind,schedulesUnwind,firstGroup);
Document theaters = mongoTemplate.aggregate(agg, Theater.class, TheaterProject.class).getRawResults();
return theaters;
}
public List<TheaterProject> getSchedules(String cityId, String spectaclesId){
MatchOperation match = Aggregation.match(Criteria.where("city_id").is(cityId).and("theatreRooms.schedules.spectacle_id").is(spectaclesId));
UnwindOperation theaterUnwind = Aggregation.unwind("theatreRooms");
UnwindOperation schedulesUnwind = Aggregation.unwind("theatreRooms.schedules");
GroupOperation firstGroup = Aggregation.group(Fields.from(
Fields.field("name", "name"),
Fields.field("room", "theatreRooms.name")))
.addToSet("theatreRooms.schedules.time").as("schedules");
Aggregation agg = Aggregation.newAggregation(match,theaterUnwind,schedulesUnwind,firstGroup);
List<TheaterProject> theaters = mongoTemplate.aggregate(agg, Theater.class, TheaterProject.class).getMappedResults();
return theaters;
}
当我调用返回映射对象的 getSchedules 方法时,_id 字段等于 null。
[
{
"_id": null,
"schedules": [
"5:15"
]
},
{
"_id": null,
"schedules": [
"6:55",
"4:35",
"10:15"
]
}
]
但是当我调用使用 getRawResults 的 getRawSchedules 时,它看起来正常。
{
"results": [
{
"_id": {
"name": "Pinokio",
"room": 2
},
"schedules": [
"5:15"
]
},
{
"_id": {
"name": "Roma",
"room": 1
},
"schedules": [
"6:55",
"4:35",
"10:15"
]
}
]
}
我不知道为什么会这样。
最佳答案
我在文档和此处没有找到有关此问题的任何信息。但我有一个解决办法。您只需将该字段从 _id
重命名为其他名称即可。例如,theaterId
。我不知道您的问题的所有要求,但您可以仅在映射级别上执行此操作。
修复映射
import org.springframework.data.mongodb.core.mapping.Field;
import java.util.List;
public class TheaterProject {
@Field("theaterId")
private TheaterId _id;
private List<String> schedules;
public TheaterId get_id() {
return _id;
}
public void set_id(TheaterId _id) {
this._id = _id;
}
public List<String> getSchedules() {
return schedules;
}
public void setSchedules(List<String> schedules) {
this.schedules = schedules;
}
}
但它需要额外的投影步骤
public List<TheaterProject> getSchedules(String cityId, String spectaclesId){
...
GroupOperation firstGroup = Aggregation.group(Fields.from(
Fields.field("name", "name"),
Fields.field("room", "theatreRooms.name")))
.addToSet("theatreRooms.schedules.time").as("schedules");
ProjectionOperation projection = Aggregation.project(Fields.from(
Fields.field("theaterId", "_id"),
Fields.field("schedules", "schedules")));
Aggregation agg = Aggregation.newAggregation( ... ,firstGroup, projection);
List<TheaterProject> theaters = mongoTemplate.aggregate(agg, "collectionName", TheaterProject.class).getMappedResults();
return theaters;
}
关于java - 聚合结果无法正确映射到 Java 对象,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/56610038/