Java URL : Get root of URL object (remove path)

Question

有没有办法从给定的 URL 中仅获取方案 + 主机 + 端口。

所以我的意思是，我想删除路径 url 段。

URL aURL = new URL("http://example.com:80/docs/books/tutorial"
                       + "/index.html?name=networking#DOWNLOADING");

我一直在玩这个:

System.out.println("protocol = " + aURL.getProtocol());
System.out.println("authority = " + aURL.getAuthority());
System.out.println("host = " + aURL.getHost());
System.out.println("port = " + aURL.getPort());
System.out.println("path = " + aURL.getPath());
System.out.println("query = " + aURL.getQuery());
System.out.println("filename = " + aURL.getFile());
System.out.println("ref = " + aURL.getRef());

输出是:

protocol = http
authority = example.com:80
host = example.com
port = 80
path = /docs/books/tutorial/index.html
query = name=networking
filename = /docs/books/tutorial/index.html?name=networking
ref = DOWNLOADING

我想要得到的是 http://example.com:8080

的新 URL 对象

有什么想法吗？

Answer 1

我发现更短的方法可以维护除路径部分之外的所有内容，请使用URI.resolve()。

URL url = new URL("http://example.com:8081/api/test");
System.out.println(url)// prints "http://example.com:8081/api/test"

URL urlNoPath = url.resolve("/");
System.out.println(url)// prints "http://example.com:8081/"