我正在尝试将音板构建到应用程序中,并找到了一种使用标签来控制播放声音的有效方法。不过,我现在正在尝试集成一个可以与 AVAudioPlayer
上的 .stop()
方法一起使用的暂停按钮,但是我当前的代码出现错误:
EXC_BAD_ACCESS
这就是我现在正在使用的,有什么想法吗?
import UIKit
import AVFoundation
let soundFilenames = ["sound","sound2","sound3"]
var audioPlayers = [AVAudioPlayer]()
class SecondViewController: UIViewController {
var audioPlayer = AVAudioPlayer()
override func viewDidLoad() {
super.viewDidLoad()
for sound in soundFilenames {
do {
let url = NSURL(fileURLWithPath: NSBundle.mainBundle().pathForResource(sound, ofType: "mp3")!)
let audioPlayer = try AVAudioPlayer(contentsOfURL: url)
audioPlayers.append(audioPlayer)
} catch {
//Catch error thrown
audioPlayers.append(AVAudioPlayer())
}
}
}
@IBAction func buttonPressed(sender: UIButton) {
let audioPlayer = audioPlayers[sender.tag]
audioPlayer.play()
}
@IBAction func stop(sender: UIButton) {
audioPlayer.stop()
}
}
最佳答案
停止功能中的audioPlayer不是播放器。您应该在buttonPressed函数中分配它。
@IBAction func buttonPressed(sender: UIButton) {
audioPlayer = audioPlayers[sender.tag]
audioPlayer.play()
}
顺便说一句,您可以将audioPlayer标记为“?”属性,初始化此Controller时会更高效。
class SecondViewController: UIViewController {
var audioPlayer: AVAudioPlayer?
let enableMuiltPlayers = false
....
@IBAction func buttonPressed(sender: UIButton) {
if sender.tag < audioPlayers.count else {
print("out of range")
return
}
if enableMuiltPlayers {
audioPlayers[sender.tag].play()
} else {
audioPlayer?.stop()
//set the current playing player
audioPlayer = audioPlayers[sender.tag]
audioPlayer?.play()
}
}
@IBAction func stop(sender: UIButton) {
let wantToStopAll = false
if enableMuiltPlayers && wantToStopAll {
stopAll()
} else {
audioPlayer?.stop()
}
audioPlayer = nil
}
}
停止所有:
fun stopAll() {
for player in audioPlayers {
player.stop()
}
}
关于ios - Swift - 停止 avaudioplayer,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/38409834/