我对下面的代码片段有疑问:
long l=9223372036854775807L;
float f=static_cast<float>(l);
long 值不能完全按照 IEEE754 表示。
我的问题是如何处理有损转换:
- 是否采用最接近的浮点表示形式?
- 是否采用下一个更小/更大的代表?
- 或者是否采取了其他方法?
我知道这个问题 what happens at background when convert int to float但这并不能回答我的问题。
最佳答案
C++ 定义这样的转换(引用最新标准草案):
[conv.fpint]
A prvalue of an integer type or of an unscoped enumeration type can be converted to a prvalue of a floating-point type. The result is exact if possible. If the value being converted is in the range of values that can be represented but the value cannot be represented exactly, it is an implementation-defined choice of either the next lower or higher representable value. [ Note: Loss of precision occurs if the integral value cannot be represented exactly as a value of the floating-point type. — end note ] If the value being converted is outside the range of values that can be represented, the behavior is undefined. If the source type is bool, the value false is converted to zero and the value true is converted to one.
IEEE 754 标准定义的转换如下:
5.4.1 Arithmetic operations
It shall be possible to convert from all supported signed and unsigned integer formats to all supported arithmetic formats. Integral values are converted exactly from integer formats to floating-point formats whenever the value is representable in both formats. If the converted value is not exactly representable in the destination format, the result is determined according to the applicable rounding-direction attribute, and an inexact or floating-point overflow exception arises as specified in Clause 7, just as with arithmetic operations. The signs of integer zeros are preserved. Integer zeros without signs are converted to +0. The preferred exponent is 0.
舍入模式指定为:
4.3.1 Rounding-direction attributes to nearest
roundTiesToEven, the floating-point number nearest to the infinitely precise result shall be delivered; if the two nearest floating-point numbers bracketing an unrepresentable infinitely precise result are equally near, the one with an even least significant digit shall be delivered.
roundTiesToAway, the floating-point number nearest to the infinitely precise result shall be delivered; if the two nearest floating-point numbers bracketing an unrepresentable infinitely precise result are equally near, the one with larger magnitude shall be delivered.
4.3.2 Directed rounding attributes
roundTowardPositive, the result shall be the format’s floating-point number (possibly +∞) closest to and no less than the infinitely precise result
roundTowardNegative, the result shall be the format’s floating-point number (possibly −∞) closest to and no greater than the infinitely precise result
roundTowardZero, the result shall be the format’s floating-point number closest to and no greater in magnitude than the infinitely precise result.
4.3.3 Rounding attribute requirements
The roundTiesToEven rounding-direction attribute shall be the default rounding-direction attribute for results in binary formats.
因此,默认情况下,您的建议 1 将适用,但前提是尚未选择其他模式。
<小时/>C++标准库继承<cfenv>
来自C标准。该 header 提供了用于与浮点环境交互的宏、函数和类型,包括舍入模式。
关于c++ - C++中如何定义从整数到 float 的精度损失?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/57870372/