我有一个从低到高排序的数组，其中有超过 260k 个值。我已经找到了数组的平均值和中位数，只需要找出众数？
我无法使用 PHP 拥有的任何数学函数，它必须全部手动完成。
我希望这样可以只有一个值作为模式，但也可以有多个值作为模式。我还需要能够记录该值的存储次数。例如，数字 51 出现了 6 次，因此我可以打印这两个值。
这是我到目前为止的代码:
$amountRecords = 0;
$totalValue = 0;
$valueArray = array();
// reads in csv file
$handle = fopen('Task1-DataForMeanMedianMode.csv', 'r');
// to skip the header names/values
fgetcsv($handle);
// creates array containing variables of csv file in ascending order
while(($row = fgetcsv($handle, "\r")) != FALSE)
{
// if amountRecords equals 0
if($amountRecords == 0)
{
// adds value from csv to array
$valueArray[] = $row[1];
} // else amountRecords does not equal 0
else
{
// if the value in array location before is greater than the current value from the csv file
if($valueArray[$amountRecords - 1] > $row[1])
{
// the current array location becomes the one in the location before
$valueArray[] = $valueArray[$amountRecords - 1];
// add the value from the csv to the location before
$valueArray[$amountRecords - 1] = $row[1];
} // if the value in the location before is not greater than the current value in the csv file
else
{
// adds value from csv to array
$valueArray[] = $row[1];
}
}
// calculates the total value of the values in csv file
$totalValue = $totalValue + $row[1];
// calculates the number of values in the csv file
$amountRecords++;
}
// calculate average value of payments
$averageValue = $totalValue / $amountRecords;
// limit integer to 2 decimal place
$average = number_format($averageValue,2,'.','');
// finds middle value
$middle = floor(($amountRecords / 2) - 1);
// calculates the median value
// if array size is even
if($amountRecords % 2 == 0)
{
// calculates median
$median = $valueArray[$middle];
}
else // if array size is odd
{
// calculate low and high values
$low = $valueArray[$middle];
$high = $valueArray[$middle + 1];
// calculates median
$median = (($low + $high) / 2);
}
// works out mode
// creates array count
$count = array();
// for each value in the valueArray
foreach( $valueArray as $value )
{
if( isset( $count[$value] ))
{
$count[$value]++;
}
else
{
$count[$value] = 1;
}
}
$mostCommon = "";
$iter = 0;
foreach( $count as $k => $v )
{
if( $v > $iter )
{
$mostCommon = $k;
$iter = $v;
}
}
$modeArray = array( "mode" => $mostCommon , "count" => $iter );
最佳答案
数字集的众数是出现次数最多的数字。您可以使用类似于以下代码的 PHP 来完成此操作:
$values = array_count_values($valueArray);
$mode = array_search(max($values), $values);
关于php - 如何在 PHP 中查找数组的众数，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/12036114/