我想从我的 API 方法返回无效的 ModelState 并尝试像在 Web Api 中一样使用:
return Request.CreateErrorResponse(HttpStatusCode.BadRequest, "Test");
但它说,
Severity Code Description Project File Line Suppression State Error CS1929 'HttpRequest' does not contain a definition for 'CreateErrorResponse' and the best extension method overload 'HttpRequestMessageExtensions.CreateErrorResponse(HttpRequestMessage, HttpStatusCode, string)' requires a receiver of type 'HttpRequestMessage'
因此,ASP.NET Core 中发生了一些变化,我应该包含 HttpRequestMessage 作为第一个参数。但如何创建它以及为什么它在响应中是必要的?
编辑:
我发现,以下代码可以返回无效模型:
return HttpBadRequest(ModelState);
但无论如何,我想知道灵活的方法来返回我自己的错误响应。
最佳答案
我发现 Mono 也没有实现这些; System.Web.Http/HttpRequestMessageExtensions
向 System.Net.Http
添加扩展方法。你可以自己做
namespace System.Web.Http
{
public static class ApiControllerExtensions
{
[System.Xml.Serialization.XmlRoot(ElementName = "Error", Namespace = "")]
public class ErrorResponse
{
public string StatusCode { get; set; }
public string Message { get; set; }
}
public static HttpResponseException CreateErrorResponseException(this ApiController controller, HttpStatusCode statusCode, string message)
{
ErrorResponse error = new ErrorResponse()
{
StatusCode = (int)statusCode + ": " + statusCode.ToString(),
Message = message
};
HttpResponseMessage responseMessage = controller.Request.CreateResponse(statusCode, error, controller.Request.GetConfiguration());
return new HttpResponseException(responseMessage);
}
}
}
关于c# - ASP.NET Core 和 CreateErrorResponse,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/35963210/