Android: background color when menu item is pressed
我执行了上面的url,但是没有任何变化。
样式.xml
<style name="PopupMenu" parent="@android:style/Widget.PopupMenu">
<item name="android:textColor">@color/font_color</item>
<item name="android:colorBackground">@color/dialog_background_color</item>
<item name="android:dropDownSelector">@drawable/listselector_popup</item>
<item name="android:listViewStyle">@style/CustomListView2</item>
</style>
<style name="CustomListView2" parent="@android:style/Widget.ListView">
<item name="android:listSelector">@drawable/listselector_popup</item>
</style>
listselector_popup.xml
<?xml version="1.0" encoding="utf-8"?>
<selector
xmlns:android="http://schemas.android.com/apk/res/android">
<item android:state_focused="true" android:state_enabled="false" android:state_pressed="true" android:drawable="@color/listselect_dialog_color" />
<item android:state_focused="true" android:state_enabled="false" android:drawable="@color/listselect_dialog_color" />
<item android:state_focused="true" android:state_pressed="true" android:drawable="@color/listselect_dialog_color" />
<item android:state_focused="false" android:state_pressed="true" android:drawable="@color/listselect_dialog_color" />
<item android:state_focused="true" android:drawable="@color/listselect_dialog_color" />
</selector>
java
Context wrapper = new ContextThemeWrapper(context, R.style.PopupMenu);
PopupMenu popup = new PopupMenu(wrapper, v);
最佳答案
创建一个名为 button_pressed.xml
的形状,如下所示......
<shape xmlns:android="http://schemas.android.com/apk/res/android">
<solid android:color="@color/blue" />
<stroke
android:width="4dp"
android:color="@color/blue" />
<padding
android:bottom="1dp"
android:left="1dp"
android:right="1dp"
android:top="1dp" />
</shape>
假设您有两个按钮,其 id
分别为 R.id.btn
和 R.id.btn1
,如下所示...
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="vertical" >
<Button
android:id="@+id/btn"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_margin="12dp"
android:background="@drawable/button_pressed"
android:onClick="onClick"
android:text="Press Me 1" />
<Button
android:id="@+id/btn2"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:layout_margin="12dp"
android:background="@drawable/button_pressed"
android:onClick="onClick"
android:text="Press Me 2" />
</LinearLayout>
按如下方式编写 onClick()
方法...这将允许您保留更改的颜色,直到按下另一个按钮。
Button button;
public void onClick(View v) {
Drawable dr = getResources().getDrawable(R.drawable.button_pressed);
dr.setColorFilter(Color.parseColor("#FF0000"), PorterDuff.Mode.SRC_ATOP);
switch (v.getId()) {
case R.id.btn:
if (button == null) {
button = (Button) findViewById(v.getId());
} else {
button.setBackgroundResource(R.drawable.button_pressed);
button = (Button) findViewById(v.getId());
}
button.setBackgroundDrawable(dr);
break;
case R.id.btn2:
if (button == null) {
button = (Button) findViewById(v.getId());
} else {
button.setBackgroundResource(R.drawable.button_pressed);
button = (Button) findViewById(v.getId());
}
button.setBackgroundDrawable(dr);
break;
default:
break;
}
}
希望这对您有用。请告诉我是否有效。
关于java - Android:按下弹出菜单项时的背景颜色,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/57439741/