我有一个具有该签名的 Spring MVC 服务:
@RequestMapping(method = RequestMethod.POST, value = "/addUser", consumes = "application/json")
public @ResponseBody User addUser(@RequestBody User user) {
这在 context.xml 中
<bean id="jacksonMessageConverter"
class="org.springframework.http.converter.json.MappingJacksonHttpMessageConverter"></bean>
<bean
class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter">
<property name="messageConverters">
<list>
<ref bean="jacksonMessageConverter" />
</list>
</property>
</bean>
我发出一个 Post 请求,但总是返回 400error->Bad request。 我写了一个过滤器来读取请求内容,是这样的:
编辑 json:
{
"email": "Anchor",
"latitude": 40.3139461,
"longitude": -3.8810229,
"name": "a",
"online": true,
"password": "a",
"deviceRegId": "APA91bGnD1EuqEm9cpoHsenC-HEphQJRniEnhPovK24QkKkLBXrDesSCP6CFlyOKwR1huwSI28Wd-DdN0N8MDKle7myYB7Dznzc3Z11ZOv3jMlJEIegykpnnnYScrElw2czQEa4pKFeQW7BklUsUS-IB15LMqH_Ag"
}
编辑:用户类别
public class User implements Serializable{
@JsonProperty("deviceRegId")
private java.lang.String deviceRegistrationID;
@JsonProperty("email")
private java.lang.String email;
@JsonProperty("latitude")
private java.lang.Double latitude;
@JsonProperty("longitude")
private java.lang.Double longitude;
@JsonProperty("name")
private java.lang.String name;
@JsonProperty("online")
private java.lang.Boolean online;
@JsonProperty("password")
private java.lang.String password;
public User(String deviceRegid) {
this.deviceRegistrationID = deviceRegid;
this.online = true;
}
public java.lang.String getDeviceRegistrationID() {
return deviceRegistrationID;
}
public java.lang.String getEmail() {
return email;
}
public void setEmail(java.lang.String email) {
this.email = email;
}
public java.lang.Double getLatitude() {
return latitude;
}
public void setLatitude(java.lang.Double latitude) {
this.latitude = latitude;
}
public java.lang.Double getLongitude() {
return longitude;
}
public void setLongitude(java.lang.Double longitude) {
this.longitude = longitude;
}
public java.lang.String getName() {
return name;
}
public void setName(java.lang.String name) {
this.name = name;
}
public java.lang.Boolean getOnline() {
return online;
}
public void setOnline(java.lang.Boolean online) {
this.online = online;
}
/**
* @return value or {@code null} for none
*/
public java.lang.String getPassword() {
return password;
}
/**
* @param password
* password or {@code null} for none
*/
public void setPassword(java.lang.String password) {
this.password = password;
}
有什么问题吗?
最佳答案
请删除参数化构造函数,然后就可以了。 :)
public User(String deviceRegid) {
this.deviceRegistrationID = deviceRegid;
this.online = true;
}
因为在数据绑定(bind)时调用默认构造函数。
检查您的 json 数据:
{
"email": "Anchor",
"latitude": 40.3139461,
"longitude": -3.8810229,
"name": "a",
"online": true,
"password": "a",
"deviceRegId": "APA91bGnD1EuqEm9cpoHsenC-HEphQJRniEnhPovK24QkKkLBXrDesSCP6CFlyOKwR1huwSI28Wd-DdN0N8MDKle7myYB7Dznzc3Z11ZOv3jMlJEIegykpnnnYScrElw2czQEa4pKFeQW7BklUsUS-IB15LMqH_Ag"
}
验证以下事项:
JSON 的名称是否与 User 类的字段名称匹配。
同时检查 User 类中相应字段名称 datatype 是否支持 JSON value。
请尝试一下,我已经多次遇到同样的问题。
关于json - Spring mvc 与 @requestbody 的错误请求,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/22102697/