java - 'while' 语句无法在不抛出异常的情况下完成 - Android

Question

通过这种方法，我每秒更新一次 TextView。

 private void UpdatingTime(final String endTime, final long diffInDays) {
            new Thread(new Runnable() {
                @Override
                public void run() {
                    while (true) {
                        try {
                            Thread.sleep(ONE_SECOND);
                            mHandler.post(new Runnable() {
                                @Override
                                public void run() {
                                    // Updating time every second
                                    long diffInHours = Methodes.diffInHours(endTime, diffInDays);
                                    long diffInMinutes = Methodes.diffInMinutes(endTime, diffInDays, diffInHours);
                                    long diffInSeconds = Methodes.diffInSeconds(endTime, diffInDays, diffInHours, diffInMinutes);

                                    tvTime2.setText(addZeroInFront(diffInHours)
                                            + ":" + addZeroInFront(diffInMinutes)
                                            + ":" + addZeroInFront(diffInSeconds));
                                }

                                private String addZeroInFront(long diffInHours) {
                                    String s = "" + diffInHours;
                                    if (s.length() == 1) {
                                        String temp = s;
                                        s = "0" + temp;
                                    }
                                    return s;
                                }
                            });
                        } catch (Exception e) {
                            e.printStackTrace();
                        }
                    }
                }
            }).start();
        }
    }

这个方法效果很好。但是我收到了这个警告:

'while' statement cannot complete without throwing an exception.

Reports for, while, or do statements which can only exit by throwing an exception. While such statements may be correct, they are often a symptom of coding errors.

我讨厌警告，我想修复它。我该如何解决这个警告，或者对于这个无限循环有更好的解决方案...？

Answer 1

此警告是误报；你应该忽略它。

通常，无限循环是某处错误的标志；在您的代码中，无限循环正是您想要的。