最佳答案
我认为没有一个简单的函数,但是用这两个函数来做应该不会太难:
julia> Pkg.dependents("Cairo")
10-element Array{AbstractString,1}:
"Tk"
"Gtk"
"Mamba"
"Drawing"
"GtkUtilities"
"ProfileView"
"Brim"
"Winston"
"EcologicalNetwork"
"VennEuler"
julia> Pkg.installed()
Dict{ASCIIString,VersionNumber} with 119 entries:
"Libz" => v"0.0.2"
"Gtk" => v"0.9.3"
"Interact" => v"0.3.0"
"ForwardDiff" => v"0.1.4"
"Benchmark" => v"0.1.0"
"AxisAlgorithms" => v"0.1.4"
"Cairo" => v"0.2.31+"
"HttpParser" => v"0.1.1"
"DataFrames" => v"0.6.10"
"Requests" => v"0.3.4"
"QuartzImageIO" => v"0.1.0+"
"Markdown" => v"0.3.0"
"Requires" => v"0.2.2"
"ArgParse" => v"0.3.0"
⋮ => ⋮
关于julia - 有没有办法在 julia-lang 中构建包依赖关系树?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/36642247/