c - 多线程导致 C 语言性能下降

标签 c multithreading performance

我正在用 C 语言实现实时信号处理算法,并尝试使用多线程并行化代码的一部分。

单线程实现的代码是

void calcTheta(float *theta, float **s, float ***q, float ***g,
               int *Ki, int m, int numObv, int numTask) {
    int i, j, k;

    for (i = 0; i < m; i++) {
        theta[i] = 0;
        for (j = 0; j < numObv; j++) {
            for (k = 0; k < numTask; k++) {
                theta[i] += (Ki[k] * (pow(fabs(q[i][j][k]), 2) / g[i][j][k]) - s[i][k]) /
                             (s[i][k] * (s[i][k] - (pow(fabs(q[i][j][k]), 2) / g[i][j][k])));
            }//k
        }//j
        theta[i] = (numTask * numObv) / theta[i];
    }//i
}

多线程实现使用线程假脱机的想法,我创建了一些线程并不断向它们发出信号以处理特定的数据数组。代码如下:

#define NUM_THREADS_THETA 2
#define TRUE 1
#define FALSE 0
#define READY 1
#define DONE 0

struct threadThetaData {
    float *theta;
    float **s;
    float ***q;
    float ***g;
    int *Ki;
    int numObv;
    int numTask;
    int threadId;
};

struct threadThetaData dataArrayTheta[NUM_THREADS_THETA];
int termThread[NUM_THREADS_THETA];
int statusThread[NUM_THREADS_THETA];
int iVal[NUM_THREADS_THETA];
pthread_mutex_t mutexThreadProc[NUM_THREADS_THETA];
pthread_mutex_t mutexMainProc[NUM_THREADS_THETA];
pthread_cond_t condThreadProc[NUM_THREADS_THETA];
pthread_cond_t condMainProc[NUM_THREADS_THETA];

void *doProcTheta(void *threadArg) {
    struct threadThetaData *myData = (struct threadThetaData *)threadArg;

    float *theta = myData->theta;
    float **s = myData->s;
    float ***q = myData->q;
    float ***g = myData->g;
    int *Ki = myData->Ki;
    int numObv = myData->numObv;
    int numTask = myData->numTask;
    int threadId = myData->threadId;

    int j, k;

    while(1) {
        //printf("thread %d waiting for signal from master..\n", threadId);
        pthread_mutex_lock(&mutexThreadProc[threadId]);
        while (statusThread[threadId] != READY)
            pthread_cond_wait(&condThreadProc[threadId], &mutexThreadProc[threadId]);
        pthread_mutex_unlock(&mutexThreadProc[threadId]);

        //printf("thread %d got signal from master..\n", threadId);

        if (termThread[threadId] == TRUE)
            pthread_exit(NULL);

        theta[iVal[threadId]] = 0;
        for (j = 0; j < numObv; j++) {
            for (k = 0; k < numTask; k++) {
                theta[iVal[threadId]] += (Ki[k]*(pow(fabs(q[iVal[threadId]][j][k]),2)/g[iVal[threadId]][j][k]) - s[iVal[threadId]][k])/(s[iVal[threadId]][k]*(s[iVal[threadId]][k] - (pow(fabs(q[iVal[threadId]][j][k]),2)/g[iVal[threadId]][j][k])));
            }//k
        }//j
        theta[iVal[threadId]] = (numTask*numObv)/theta[iVal[threadId]];

        pthread_mutex_lock(&mutexMainProc[threadId]);
        statusThread[threadId] = DONE;
        pthread_cond_signal(&condMainProc[threadId]);
        pthread_mutex_unlock(&mutexMainProc[threadId]);

        //printf("thread %d signaled to master..\n", threadId);
    }
}

void calcTheta(float *theta,float **s,float ***q,float ***g,int *Ki,int m, int numObv, int numTask)
{
    int i,j;

    pthread_t thetaThreads[NUM_THREADS_THETA];
    int numThreadBlks = m/NUM_THREADS_THETA;
    int numThreadRem = m%NUM_THREADS_THETA;
    int mCount = 0;

    for(i=0;i<NUM_THREADS_THETA;i++)
    {
        pthread_mutex_init(&mutexThreadProc[i], NULL);
        pthread_mutex_init(&mutexMainProc[i], NULL);
        pthread_cond_init (&condThreadProc[i], NULL);
        pthread_cond_init (&condMainProc[i], NULL);
        dataArrayTheta[i].theta = theta;
        dataArrayTheta[i].s = s;
        dataArrayTheta[i].q = q;
        dataArrayTheta[i].g = g;
        dataArrayTheta[i].Ki = Ki;
        dataArrayTheta[i].numObv = numObv;
        dataArrayTheta[i].numTask = numTask;
        dataArrayTheta[i].threadId = i;
        termThread[i] = FALSE;
        statusThread[i] = DONE;
        pthread_create(&thetaThreads[i],NULL,doProcTheta,(void *)&dataArrayTheta[i]);

    }

    for(i=0;i<numThreadBlks;i++)
    {
        for(j=0;j<NUM_THREADS_THETA;j++)
        {
            pthread_mutex_lock(&mutexThreadProc[j]);
            statusThread[j] = READY;
            iVal[j] = mCount;
            mCount++;
            pthread_cond_signal(&condThreadProc[j]);
            pthread_mutex_unlock(&mutexThreadProc[j]);
            //printf("Signaled thread %d from master ... Waiting  on signal ..\n",j);
        }

        for(j=0;j<NUM_THREADS_THETA;j++)
        {
            pthread_mutex_lock(&mutexMainProc[j]);
            while (statusThread[j] != DONE)
                pthread_cond_wait(&condMainProc[j], &mutexMainProc[j]);
            pthread_mutex_unlock(&mutexMainProc[j]);
            //printf("Got signal from thread %d to  master \n",j);
        }

    }

    for(j=0;j<numThreadRem;j++)
    {
        pthread_mutex_lock(&mutexThreadProc[j]);
        statusThread[j] = READY;
        iVal[j] = mCount;
        mCount++;
        pthread_cond_signal(&condThreadProc[j]);
        pthread_mutex_unlock(&mutexThreadProc[j]);
    }

    for(j=0;j<numThreadRem;j++)
    {
        pthread_mutex_lock(&mutexMainProc[j]);
        while (statusThread[j] != DONE)
            pthread_cond_wait(&condMainProc[j], &mutexMainProc[j]);
        pthread_mutex_unlock(&mutexMainProc[j]);
    }

    for(j=0;j<NUM_THREADS_THETA;j++)
    {
        pthread_mutex_lock(&mutexThreadProc[j]);
        statusThread[j] = READY;
        termThread[j] = TRUE;
        pthread_cond_signal(&condThreadProc[j]);
        pthread_mutex_unlock(&mutexThreadProc[j]);

        pthread_join(thetaThreads[j],NULL);

        pthread_mutex_destroy(&mutexThreadProc[j]);
        pthread_cond_destroy(&condThreadProc[j]);
        pthread_mutex_destroy(&mutexMainProc[j]);
        pthread_cond_destroy(&condMainProc[j]);
    }

}

数组维度:

float theta[m];
float s[m][numTask];
float q[m][numObv][numTask];
float g[m][numObv][numTask];
int Ki[numTask];

对于特定数据集,其中

m=661
numObv=96
numTask=1024

运行时间是:

Single threaded : 4.5 seconds
Multithreaded with 2 threads : 6.9 seconds 

我希望多线程代码的运行时能够比单线程代码带来一些性能改进,而反之亦然。如果有人指出我在这里缺少的内容,我将不胜感激。

最佳答案

对于当前的问题,您的多线程实现似乎过于复杂。单线程代码显示每个 theta元素的计算独立于所有其他 theta元素。

因此,您不需要互斥体和条件,因为线程之间不需要数据交换/同步。只需让线程处理 theta 的不同范围即可。计算。

m=661和 2 个线程,那么第一个线程应该计算 theta在 0..330 范围内,第二个线程应该计算 theta范围 331..660。启动两个线程并等待它们完成(也称为联接)。

您几乎可以使用单线程代码来实现多线程。您所需要的只是向函数添加一个起始索引。

关于c - 多线程导致 C 语言性能下降,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/38870492/

相关文章:

c - 在 C 中动态存储数组值

c - 哪个 C99 编译器(Clang 与 GCC)更接近 const 结构字段的标准?

python - 我可以从 C main() 程序返回一个字符串吗

Java线程生命周期

Android TListBox 滚动不流畅

performance - drawRect 性能

c++ - 如何建立一个具有cmake文件的c++/c项目?

c# - 如何等待一个方法在另一个线程上完成?

Java Thread.interrupted 和中断标志

c# - 设计库性能比较测试