averageLength
获取用户在上一个案例中输入的所有单词并获取平均单词数。 switch 语句位于 main 方法下(此处未显示),但是当我尝试实现案例 3 来获取平均值时,它不起作用,因为 average
未在 main
下声明code> 方法,位于 averageLength
下。我怎样才能解决这个问题?谢谢
import java.util.Scanner;
import java.util.Arrays;
/**
* Word Manager
*
* @author Harry
*/
public class WordManager {
/**
* Adds the word to the next empty space in the array, if there is space.
* Returns the new size of the array.
*/
public static int add(String[] words, int count, String word) {
if (count < words.length) {
words[count] = word;
count++;
} else {
System.out.println("The array is full");
}
return count;
}
/** Displays the words in the collection as a comma separated list. */
public static void printList(String[] words, int count) {
}
public static void averageLength(String[] words, int count) {
Scanner sc = new Scanner(System.in);
double average;
double sum;
while (sc.hasNext()) {
String userInput = sc.next();
double charNum = userInput.length();
sum = charNum + sum;
count++;
if (count > 0) {
average = sum / count;
System.out.println("Average word length = " + average);
}
}
}
public static void main(String[] args ) {
Scanner sc = new Scanner(System.in);
String[] words = new String[20];
int count = 0;
String aWord;
int choice;
do {
System.out.println("\t MENU:");
System.out.println("1. Add a word");
System.out.println("2. Display words:");
System.out.println("3. Display average word length");
System.out.println("4. Quit");
System.out.println("Enter option: ");
choice = sc.nextInt();
System.out.println("choice = "+choice);
switch (choice) {
case 1:
System.out.println("Add a word");
aWord = sc.next();
count = add(words, count, aWord);
break;
case 2:
System.out.println("Display words");
System.out.println("We have an array of " + words.length + " integers: " + Arrays.toString(words));
break;
case 3:
averageLenth();
break;
default:
System.out.println("Invalid responce");
}
} while (choice >= 0 && choice < 4);
}
}
最佳答案
您粘贴的代码存在一些问题 - 其中一些问题已在之前的评论/答案中找到,但为了完整起见,我也会在此处列出它们:
averageLenth
名称中的拼写错误 - 更改为averageLength
。因此,您的代码将无法编译。- 调用站点未遵循
averageLength(String[] Words, int count)
的签名 - 在调用时更改为averageLength(words, count)
位于交换机内部。 averageLength
的实现不正确 - 您的实现实际上并不是迭代单词数组并计算平均值,而是似乎要求扫描器提供下一个输入。我更改了下面代码中的实现,以通过迭代单词数组来计算平均值。import java.util.Scanner; import java.util.Arrays; /** * Word Manager * * @author Harry */ public class WordManager { /** * Adds the word to the next empty space in the array, if there is space. * Returns the new size of the array. */ public static int add(String[] words, int count, String word) { if (count < words.length) { words[count] = word; count++; } else { System.out.println("The array is full"); } return count; } /** * Displays the words in the collection as a comma separated list. */ public static void printList(String[] words, int count) { } private static void averageLength(String[] words, int count) { int sum=0; for(int word =0; word < count; word++){ int wordLength = words[word].length(); sum += wordLength; } double averageWorldLength = sum/count; System.out.println("Average word length = " +averageWorldLength; } public static void main(String[] args) { Scanner sc = new Scanner(System.in); String[] words = new String[20]; int count = 0; String aWord; int choice; do { displayMenuOptions(); choice = sc.nextInt(); System.out.println("choice = " + choice); switch (choice) { case 1: System.out.println("Add a word"); aWord = sc.next(); count = add(words, count, aWord); break; case 2: System.out.println("Display words"); System.out.println("We have an array of " + words.length + " integers: " + Arrays.toString(words)); break; case 3: averageLength(words, count); break; default: System.out.println("Invalid responce"); } } while (choice >= 0 && choice < 4); } private static void displayMenuOptions() { System.out.println("\t MENU:"); System.out.println("1. Add a word"); System.out.println("2. Display words:"); System.out.println("3. Display average word length"); System.out.println("4. Quit"); System.out.println("Enter option: "); } }
关于Java - 如何在 switch 语句中调用方法?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/58231868/