Android BroadcastReceiver android.intent.action.BATTERY_CHANGED

Question

我能够在我的 Activity 中收听 Intent Intent.ACTION_BATTERY_CHANGED 并且效果很好。我尝试在 list 中定义接收器:

<receiver android:name="com.beargreaves.battery.BatteryReceiver"> 
    <intent-filter> 
        <action android:name="android.intent.action.BATTERY_CHANGED" />
    </intent-filter> 
</receiver>

但它没有用，我在这里读了一篇文章说它必须以编程方式定义。我不想在我的 Activity 中注册接收器，而是想在服务中实现这一点，以便它持续监控。我已经成功地做到了这一点，而且它有效，但我想检查我的工作，看看它是否是正确的方法。

我从扩展 BroadcastReceiver 开始:

public class BatteryReceiver extends BroadcastReceiver{
    @Override
    public void onReceive(Context context, Intent intent) {
        Bundle bundle = intent.getExtras();

        if(null == bundle)
            return;

        boolean isPresent = intent.getBooleanExtra("present", false);
        String technology = intent.getStringExtra("technology");
        int plugged = intent.getIntExtra("plugged", -1);
        int scale = intent.getIntExtra("scale", -1);
        int health = intent.getIntExtra("health", 0);
        int status = intent.getIntExtra("status", 0);
        int rawlevel = intent.getIntExtra("level", -1);
        int level = 0;

        Log.d("Debug","Battery Receiver OnReceive");

        if(isPresent) {
            if (rawlevel >= 0 && scale > 0) {
                level = (rawlevel * 100) / scale;

                Log.d("Debug","BatterReceiver: " + level);

                Toast.makeText(context,"Battery Receiver: " + level + "\t" + status + "Raw: " + rawlevel,Toast.LENGTH_LONG).show();

                if(level <60) {
                    /*
                     * Only invoke the service when level below threshold
                     */
                    Intent i = new Intent(context, BatteryService.class);
                    i.putExtra("level", level);
                    context.startService(i);
                }
            }
        }
    }
}

然后我使用服务首先在 onCreate() 中注册接收器，然后在 onStart() 中处理事件。如果级别低于阈值，我的 BroadcastReceiver 将启动服务。

public class BatteryService extends Service {
    /*
     * First Call to onStart we don't want to do anything
     */
    boolean avoidFirst = false;
    private BroadcastReceiver receiver;

    @Override
    public IBinder onBind(Intent intent) {
        // TODO Auto-generated method stub
        return null;
    }

    @Override
    public void onCreate() {
        super.onCreate();

        IntentFilter filter = new IntentFilter(Intent.ACTION_BATTERY_CHANGED);
        receiver = new BatteryReceiver();
        registerReceiver(receiver, filter);
    }

    @Override
    public void onStart(Intent intent, int startId) {
        Log.d("Debug","Battery Service On Start");
        int level = intent.getIntExtra("level", -1);

        if(avoidFirst) {
            if(level != -1) {
                Log.d("Debug","Battery Alert Notifying..... " + level);
                SMSManager.sendSMS(BatteryService.this, "<number redacted>", "Battery Level Aleart: " + level);
                stopSelf();
            }
        } else {
            avoidFirst = true;
        }
    }

    @Override
    public void onDestroy() {
        // TODO Auto-generated method stub
        super.onDestroy();
        PreferenceUtil.updatePreference(BatteryService.this, "battery_monitor_on", false);
        unregisterReceiver(receiver);
    }
}

这是正确的做法吗？就是在 onCreate() 中注册接收者，然后在接收到事件时启动服务。首先，我尝试不使用服务，但后来我无法注册接收者，因为它无法在 list 中实现。其次，当我尝试在 onReceive() 中发送文本消息时抛出异常。我读到 onReceive() 不应该启动任何线程。

提前致谢

Answer 1

是的，这是正确的做法。这与我对我的应用程序所做的非常相似，该应用程序在生产环境中运行良好已有十多年(自 Android 早期以来)，而且我看不到您在这里遗漏或出错的任何内容。你是对的，你不能从你的 list 中注册那个广播；您确实需要以编程方式这样做。根据您分享的其他内容，在服务而不是 Activity 中这样做显然是正确的。