我可以将下面三个非常相似的函数合并为一个函数吗?
所有三个函数都会更新数据库中的特定列。 update语句中的匿名对象用于更新相应的列。匿名对象中的成员名称不应更改,因为它是数据库中列的名称。
我正在使用 ormlite-servicestack 进行数据库连接。我使用的数据库是 Microsoft SQLServer 2012。
函数1:
//Updating the call status.
private void UpdateCallStatus(string claimId, bool isDisconnected)
{
_LogFactory.LogInfo(this.GetType(), "Updating call status....\n");
IDbConnectionFactory maConnectionFactory = new DatabaseConnection().getConnection();
using (var db = maConnectionFactory.Open())
{
db.Update<IVRSCallDetails>(new { IsDisconnected = isDisconnected }, where: callDetail => callDetail.ClaimId == claimId);
}
}
函数2:
//Updating the selected dtmf by the client using the claimid.
private void UpdateDtmf(string claimId, string selectedDtmf)
{
_LogFactory.LogInfo(this.GetType(), "Updating Selected DTMF:" + selectedDtmf + "\n");
IDbConnectionFactory maConnectionFactory = new DatabaseConnection().getConnection();
using (var db = maConnectionFactory.Open())
{
db.Update<IVRSCallDetails>(new { SelectedDTMF = selectedDtmf }, where: callDetail => callDetail.ClaimId == claimId);
}
}
功能3:
//Updating the isCallMade value..
private void updateIsCallMade(string claimId, bool isCallMade)
{
_LogFactory.LogInfo(this.GetType(), "Call has been made to the client with claim id: " + claimId + "\n");
IDbConnectionFactory maConnectionFactoruy = new DatabaseConnection().getConnection();
using (var db = maConnectionFactoruy.Open())
{
db.Update<IVRSCallDetails>(new { IsCallMade = isCallMade }, where: callDetail => callDetail.ClaimId == claimId);
}
}
最佳答案
您可以将其更改为通用方法(以便能够传递类型)以及 Func<object>
代替第二个参数来生成匿名对象。
private void updateData<T>(string claimId, Func<object> data)
{
_LogFactory.LogInfo(this.GetType(), "Call has been made to the client with claim id: " + claimId + "\n");
IDbConnectionFactory maConnectionFactoruy = new DatabaseConnection().getConnection();
using (var db = maConnectionFactoruy.Open())
{
db.Update<T>(data(), where: callDetail => callDetail.ClaimId == claimId);
}
}
使用
updateData<IVRSCallDetails>("123", () => new { IsCallMade = true});
updateData<IVRSCallDetails>("123", () => new { SelectedDTMF = selectedDtmf});
关于c# - 我可以将这三个相似的函数合并为一个函数吗?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41482666/