我正在尝试编写一个递归算法来计算斐波那契数。然而,该程序在打印结果方面遇到了困难。
我的想法是将每个计算值存储到一个数组中(这样算法应该更快)。
我想要的输出:
The fibonacci of n = 1 is fn= 1
The fibonacci of n = 2 is fn= 2
The fibonacci of n = 3 is fn= 2
The fibonacci of n = 4 is fn= 3
...
The fibonacci of n = 8 is fn= 21
public class fibonacciCalculator {
static int[] arr = new int[50];
static int fibo (int n, int arr[]) {
if ( n == 0 ) {
return 0;
}else if ( n == 1 ) {
return 1;
}
if ( arr[n-1] == 0) {
arr[n-1] = fibo(n-1, arr);
}
if ( arr[n-2] == 0) {
arr[n-2] = fibo(n-2, arr);
}
return arr[n-1] + arr[n - 2];
}
public static void main(String[] args) {
for (int i = 1; i == 8; i++) {
if (arr [i] == 0) {
fibo(i, arr);
int x = arr[i];
String a = String.format("The fibonacci of n = %d is fn= %d", i , x);
System.out.println(a);
}
}
}
}
最佳答案
您可以在不声明数组的情况下执行此操作。这样,中间值就存储在执行堆栈中:
public class fibonacciCalculator {
static int fibo (int n) {
if ( n == 0 ) {
return 0;
} else if ( n == 1 ) {
return 1;
} else {
return fibo(n-2) + fibo(n-1);
}
}
public static void main(String[] args) {
for (int i = 1; i <= 8; i++) {
int x = fibo(i);;
String a = String.format("The fibonacci of n = %d is fn= %d", i , x);
System.out.println(a);
}
}
}
关于java - 打印出斐波那契数列,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/58780595/