我使用任何休息客户端点击下面的网址,我得到了 api 响应:400 带响应正文的错误请求
输入参数
POST http://SOME.IP:8008/equipment_api/F0-03-8C-C3-D3-CC/832
HEADERS
Content-Type application/json
X-RequestID 1234
BODY
{
"items":[{"updateValue":1, "updateKey": "RESETDEV"}],
"sync":"false"
}
Response :400 Bad Request
{
"error": "RESETDEV is not a valid key."
}
但是java简单客户端不显示响应正文..下面是java代码..它只是给出400错误请求。
public static void main(String[] args) {
try {
String urlParameters = " {\r\n" +
"\"items\":[{\"updateValue\":\"Hi\", \"updateKey\": \"RESETDEV\"}],\r\n" +
"\"sync\":false\r\n" +
"}";
URL url = new URL("http://SOME.IP:8008/equipment_api/F0-03-8C-C3-D3-CC/832");
URLConnection conn = url.openConnection();
conn.setRequestProperty("content-type", "application/json");
conn.setRequestProperty("X-RequestID", "1234");
conn.setDoOutput(true);
OutputStreamWriter writer = new OutputStreamWriter(conn.getOutputStream());
writer.write(urlParameters);
writer.flush();
String line;
BufferedReader reader = new BufferedReader(new InputStreamReader(conn.getInputStream()));
while ((line = reader.readLine()) != null) {
System.out.println(line);
}
writer.close();
reader.close();
}catch(Exception ex) {
System.out.println("some error :: "+ex.toString());
}
}
最佳答案
尝试使用以下代码
final String uri = "http://SOME.IP:8008/equipment_api/F0-03-8C-C3-D3-CC/832";
RestTemplate restTemplate = new RestTemplate();
HttpHeaders headers = new HttpHeaders();
headers.setAccept(Arrays.asList(MediaType.APPLICATION_JSON));
HttpEntity<String> entity = new HttpEntity<String>("X-RequestID", "1234");
ResponseEntity<String> result = restTemplate.exchange(uri, HttpMethod.GET, entity, String.class);
System.out.println(result);
用 Try Catch 包裹起来。
关于如果请求错误,java 休息调用响应主体会丢失,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/58950267/