java - 如何从 Volley Api 字符串响应中查找特定数据

Question

我是 API 新手，终于弄清楚如何成功从网站检索请求响应。问题是我完全不知道该如何处理这个回应。我不知道如何访问响应中的某些值

这是我的 API Volley 代码

  RequestQueue requestQueue = Volley.newRequestQueue(this);
    String uri = Uri.parse("https://chicken-coop.p.rapidapi.com/games/Fortnite?platform=pc")
            .buildUpon()
            .build().toString();

    StringRequest stringRequest = new StringRequest(
            Request.Method.GET, uri, new Response.Listener<String>() {
        @Override
        public void onResponse(String response) {
            displayResults.setText("Response: " + response.substring(0,500));

        }

    }, new Response.ErrorListener() {

        @Override
        public void onErrorResponse(VolleyError error) {
             displayResults.setText( "" + error.toString());
        }

    }) {

        @Override
        public Map<String, String> getHeaders() throws AuthFailureError {
            Map<String, String> params = new HashMap<>();
            params.put("X-RapidAPI-Key", "5cdb2bbe57mshd9242c8d3177cb3p16f2fbjsnd7c5829eb4ad");
            params.put("X-RapidAPI-Host", "chicken-coop.p.rapidapi.com");
            return params;
        }
    };
    requestQueue.add(stringRequest);

这是我收到的响应查询

"result":{10 items "title":"Fortnite" "releaseDate":"Jul 25, 2017" "description":"Epic Games next project has you building forts and stopping a zombie invasion." "genre":[... ]6 items "image":"https://static.metacritic.com/images/products/games/5/c7eb46ceb7da9c72c5a95193e8621faf-98.jpg" "score":81 "developer":"Epic Games" "publisher":[... ]1 item "rating":"T" "alsoAvailableOn":[6 items 0: "iPhone/iPad" 1: "PlayStation 3" 2: "PlayStation 4" 3: "Switch" 4: "Xbox 360" 5: "Xbox One"

如何从响应查询中查找显式值？我一直在网上寻找如何做到这一点，有很多不同的方法可以进行，但我不知道该怎么做。例如，我如何才能将发布日期放入其自己的文本框中？当我使用字符串响应时，我在网上看到的大多数示例都使用 JsonObjects

Answer 1

在您的 onResponse 方法中，您需要解析结果，以便提取您想要的任何数据

public void onResponse(String response) {
        try {
            JSONObject jsonObject = new JSONObject(response);
            JSONArray jsonArray = jsonObject.getJSONArray("result");
             // toaccess to your json data 
                String title = jsonArray.getString("title");
                // your code 


        } catch (JSONException e) {
            e.printStackTrace();
        }
    }