java - 从android解析jsonObject并在webservice vb.net中获取它

Question

我已经解决了问题，

我认为我的问题是我不知道如何在 webservice .NET 中获取 JSON

我使用 android studio 将 JSON 对象解析到我的 web 服务，JSON 数组和 JSON 对象正在工作，

但是我收到了一个错误的请求(也许是因为我无法在网络服务中获取 JSON？)

            JSONObject jsonObject = new JSONObject();
            jsonObject.put("horary", jsonArray);
            URL url = new URL("URL");
            HttpURLConnection conn = (HttpURLConnection) url.openConnection();
            conn.setRequestMethod("POST");
            conn.setConnectTimeout(4000);
            conn.setRequestProperty("Content-Type", "application/json");
            conn.setRequestProperty("Accept","application/json");
            conn.setDoOutput(true);
            DataOutputStream os = new DataOutputStream(conn.getOutputStream());
            os.writeBytes(URLEncoder.encode(jsonObject.toString(), "UTF-8"));
            os.flush();
            os.close();
            Log.d("json", conn.getResponseMessage());<- bad Request

这是我来自 webservice vb.net 的代码。我不知道如何获取 JSON 对象

     <WebInvoke(ResponseFormat:=WebMessageFormat.Json, UriTemplate:="Change/")>
        Function HReceiver(horary As String) As String Implements IService.HReceiver

我想我用 (horary As String) 得到了 JSON，并且我尝试了很多方法来反序列化，

但这不是重点，因为我想我无法获取 JSON

            Dim ser As JavaScriptSerializer = New JavaScriptSerializer()
            Dim horary As ArrayHorary
            Dim result As String
            Try
                Dim items = Newtonsoft.Json.JsonConvert.DeserializeObject(Of ArrayHorary())(horary)
                result = horary.ToString
            Catch ex As Exception
                result = ex.ToString
            End Try
            Return result
        End Function

        Public Class ArrayHorary
            Public Property id As String
            Public Property name As String
        End Class

谢谢您的宝贵时间

------------我解决了

<OperationContract()>
    Function HReceiver(horary As Horar) As String

    <DataContract()>
Public Class Horar
    <DataMember()>
    Public Property horary As List(Of Horari)
End Class

    <DataContract()>
Public Class Horari
    <DataMember()>
    Public Property id As String
    <DataMember()>
    Public Property name As String

End Class

服务中

<WebInvoke(ResponseFormat:=WebMessageFormat.Json, UriTemplate:="Change/")>
    Function HReceiver(horar As Horar) As String Implements IService.HReceiver
        Dim result As String

        result = horar.horary(0).name
return result

并且无需解串器即可工作

在android中，我必须使用

os.writeChars(URLEncoder.encode(jsonObject.toString(), "UTF-8"));

Answer 1

要以正确的方式接收 JSON 对象，您必须拥有一个与函数参数具有相同结构的类，例如，如果您正在接收此对象的列表，则 api 参数应该是:

Function SpoolsList(objVar As List(Of ArrayHorary)) As IHttpActionResult
    Your code
End Function

然后它会自动解析该对象。