java - 更改 SOAP xml 响应中的标记名称(类中的字段和响应中的标记必须不同)

Question

我有这样的类(class):

@Root(name = "address_v1", strict = false)
public class AddressItem {

    @Attribute(name = "idAddress")
    private Long addressId;

    @Attribute(name = "idClient")
    private Long clientId;
...
}

我有回应:

...
<ax23:address xsi:type="ax24:AddressItem">
   <ax24:addressId>1111</ax24:addressId>
   <ax24:clientId>1109</ax24:clientId>
...

但我需要:

<ax23:address xsi:type="ax24:AddressItem">
   <ax24:idAddress>1111</ax24:idAddress>
   <ax24:idClient>1109</ax24:idClient>

注释@Attribute(name = "idAddress")不起作用。 (org.simpleframework.xml.Attribute)。

我使用 wsdl2java 作为 wsdl 创建者。

Answer 1

尝试执行以下步骤并修改您的 POJO 类，如下所示，

• 对 XML 元素使用 @Element 注释，而不是 @Attribute 注释 ( please refer to documentation for more info )

  The Element annotation is used to represent a field or method that appears as an XML element.

• 将相关的 xml 元素名称设置为 @Root 和 @Element 注解

AddressItem.java

@Root(name = "ax23:address", strict = false)
public class AddressItem {

    @Element(name = "ax24:addressId")
    private Long addressId;

    @Element(name = "ax24:clientId")
    private Long clientId;
    ...
}