java - 为什么我的java猜谜游戏中的变化难度while循环没有重复？

Question

我是一名初学者程序员，我制作了这个猜数字游戏，它会生成一个随机数(范围取决于所选的难度)。我试图做到这一点，以便用户在想要更改选择时能够重新选择他们的难度。我用的是 while (changeDifficulty == true) 尝试执行此操作，但是在运行代码时，无论用户输入如何，循环都不会重复。有什么建议么？谢谢。

    //Create a random number for the user to guess
    int theNumber = 0;
    Boolean changeDifficulty = true;



        do {

            while (changeDifficulty == true) {

                System.out.println("Welcome to the number guessing game! \nSelect your difficulty (easy, medium, or hard.)");
                String difficulty = "";
                difficulty = scan.nextLine();

                if (difficulty.equalsIgnoreCase("easy")) {
                    theNumber = (int)(Math.random() * 100 + 1);
                } else if (difficulty.equalsIgnoreCase("medium")) {
                    theNumber = (int)(Math.random() * 1000 + 1);
                } else if (difficulty.equalsIgnoreCase("hard")) {
                    theNumber = (int)(Math.random() * 10000 + 1); 
                }

                String correctDifficulty = "";

                if (difficulty.equalsIgnoreCase("easy")) {
                    System.out.println("You have selected " + difficulty + " meaning you must guess a number from 1-100"
                            + " is this okay? (y/n)");
                    correctDifficulty = scan.nextLine();
                    if (correctDifficulty.equalsIgnoreCase("n")) {
                        changeDifficulty = false;
                    }
                } else if (difficulty.equalsIgnoreCase("medium")) {
                    System.out.println("You have selected " + difficulty + " meaning you must guess a number from 1-1000"
                            + " is this okay? (y/n)");
                    correctDifficulty = scan.nextLine();
                    if (correctDifficulty.equalsIgnoreCase("n")) {
                        changeDifficulty = false;
                    }
                } else if (difficulty.equalsIgnoreCase("hard")) {
                    System.out.println("You have selected " + difficulty + " meaning you must guess a number from 1-10000"
                            + " is this okay? (y/n)");
                    correctDifficulty = scan.nextLine(); 
                    if (correctDifficulty.equalsIgnoreCase("n")) {
                        changeDifficulty = false;
                    }
                }

            }
        System.out.println(theNumber);
        int guess = 0;
        int numberOfTries = 0;
        while (guess != theNumber) {
            System.out.println("Guess a number between 1 and 100:");
            guess = scan.nextInt();
            numberOfTries = numberOfTries + 1;
            if (guess < theNumber) {
                System.out.println(guess + " is too low. Try again.");
            } else if (guess > theNumber) {
                System.out.println(guess + " is too high. Try again.");
            } else {
                System.out.println(guess + " is correct. You win! You took " + numberOfTries + " tries.");
            }
        }//end of while loop for guessing 
        System.out.println("Would you like to play again (y/n)?");
        playAgain = scan.next();
    } while (playAgain.equalsIgnoreCase("y"));
    System.out.println("Thanks for playing! Goodbye!");
    scan.close();
}

Answer 1

欢迎来到 Java 世界!

代码本身没有错误，但它没有按照我们想要的方式工作。让我们找出问题所在。

    while (changeDifficulty == true) {

        System.out.println("Welcome to the number guessing game! \nSelect your difficulty (easy, medium, or hard.)");
        String difficulty = "";
        difficulty = scan.nextLine();

        if (difficulty.equalsIgnoreCase("easy")) {
            theNumber = (int)(Math.random() * 100 + 1);
        } else if (difficulty.equalsIgnoreCase("medium")) {
            theNumber = (int)(Math.random() * 1000 + 1);
        } else if (difficulty.equalsIgnoreCase("hard")) {
            theNumber = (int)(Math.random() * 10000 + 1); 
        }

        String correctDifficulty = "";

        if (difficulty.equalsIgnoreCase("easy")) {
            System.out.println("You have selected " + difficulty + " meaning you must guess a number from 1-100"
                    + " is this okay? (y/n)");
            correctDifficulty = scan.nextLine();
            if (correctDifficulty.equalsIgnoreCase("n")) {
                changeDifficulty = false;
            }
        } else if (difficulty.equalsIgnoreCase("medium")) {
            System.out.println("You have selected " + difficulty + " meaning you must guess a number from 1-1000"
                    + " is this okay? (y/n)");
            correctDifficulty = scan.nextLine();
            if (correctDifficulty.equalsIgnoreCase("n")) {
                changeDifficulty = false;
            }
        } else if (difficulty.equalsIgnoreCase("hard")) {
            System.out.println("You have selected " + difficulty + " meaning you must guess a number from 1-10000"
                    + " is this okay? (y/n)");
            correctDifficulty = scan.nextLine(); 
            if (correctDifficulty.equalsIgnoreCase("n")) {
                changeDifficulty = false;
            }
        }

    }

我发现了其中可疑的部分，所以让我们一一分析一下。 如果玩家在您提出的代码进入“替换难度”步骤时按“n”[替换难度]，则 changeDiffinity 将固定为 false，并且因此，每个游戏的 while(changeDifficulty ==true) 循环将被忽略。

因此，我们的玩家继续以相同的数字和相同的难度进行游戏。

让我们修改代码，让玩家可以正常改变难度级别，并重置数字和句子输出(1和100)，以便难度级别改变后!

这是放入一个名为changeDifficient的新 boolean 值的一种方法，但是如何比较玩家输入的正确的Difficiency呢？如下。

while(changeDifficulty == true) -> do{  }while(correctDifficulty.equalsIgnoreCase("n"));

像这样

 String correctDifficulty = "";
 String numberRange ="";
...
...



 do  {

     System.out.println("Welcome to the number guessing game! \n"
     + "Select your difficulty (easy, medium, or hard.)");

     difficulty = scan.nextLine();


     if (difficulty.equalsIgnoreCase("easy")) {
             theNumber = (int)(Math.random() * 100 + 1);
             numberRange = "1 to 100";
      } else if (difficulty.equalsIgnoreCase("medium")) {
             theNumber = (int)(Math.random() * 1000 + 1);
             numberRange = "1 to 1000";
      } else if (difficulty.equalsIgnoreCase("hard")) {
             theNumber = (int)(Math.random() * 10000 + 1); 
             numberRange = "1 to 10000";
       }

       //Change Difficulty 
        System.out.println("You have selected " + difficulty +
                            " and it means you must guess a number from "+ numberRange  //It depends on the level of difficulty.
                   + " is this okay? (y/n)");

       correctDifficulty = scan.nextLine();


       }while(correctDifficulty.equalsIgnoreCase("n"));

希望对您有一点帮助，如果有什么难以理解的地方，请留言!希望您有一个平静的一天!

<小时/> <小时/>

这是整个代码的改编。不过，我强烈建议您在看到此代码之前尝试自己的方式。

因为这也不是完美的方式。

import java.util.Scanner;

public class StackOver
{

    public static void main(String[] args) {

        Scanner scan = new Scanner(System.in);

          //Create a random number for the user to guess
        String playAgain = "";
        int theNumber = 0;
        String difficulty = "";
        String correctDifficulty = "";
        String numberRange ="";

            do {


                do  {

                    System.out.println("Welcome to the number guessing game! \n"
                            + "Select your difficulty (easy, medium, or hard.)");

                    difficulty = scan.nextLine();


                    if (difficulty.equalsIgnoreCase("easy")) {
                        theNumber = (int)(Math.random() * 100 + 1);
                        numberRange = "1 to 100";
                    } else if (difficulty.equalsIgnoreCase("medium")) {
                        theNumber = (int)(Math.random() * 1000 + 1);
                        numberRange = "1 to 1000";
                    } else if (difficulty.equalsIgnoreCase("hard")) {
                        theNumber = (int)(Math.random() * 10000 + 1); 
                        numberRange = "1 to 10000";
                    }

                    //Change Difficulty 
                    System.out.println("You have selected " + difficulty +
                            " and it means you must guess a number from "+ numberRange  //It depends on the level of difficulty.
                            + " is this okay? (y/n)");

                    correctDifficulty = scan.nextLine();


                }while(correctDifficulty.equalsIgnoreCase("n"));


            System.out.println(theNumber); //oㅁo!


            int guess = 0;
            int numberOfTries = 0;
            while (guess != theNumber) {
                System.out.println("Guess a number between " + numberRange);
                guess = scan.nextInt();

                numberOfTries = numberOfTries + 1;
                //numberOfTries += 1;
                //numberOfTries ++; 
                //also make sense and shorter!

                if (guess < theNumber) {
                    System.out.println(guess + " is too low. Try again.");
                } else if (guess > theNumber) {
                    System.out.println(guess + " is too high. Try again.");
                } else {
                    System.out.println(guess + " is correct. You win! You took " + numberOfTries + " tries.");
                }
            }//end of while loop for guessing 

            System.out.println("Would you like to play again (y/n)?");
            playAgain = scan.next();

        } while (playAgain.equalsIgnoreCase("y"));
        System.out.println("Thanks for playing! Goodbye!");
        scan.close();
    }

 }