例如,我有一个 Job 实体和一个 Worker 实体。 当我添加新工作时,我想为其分配工作人员,但不是将其用户添加到 再次数据库(并创建重复项)我只想更新工作人员 (当我使用 worker 列表创建新工作时向其中添加工作)
示例:
@Entity
@Table(name = "job")
@Getter
@Setter
@NoArgsConstructor
@AllArgsConstructor
public class Job{
@Id
@Column(name = "id")
private Long id;
@OneToMany(mappedBy = "job", fetch = FetchType.EAGER)
private Set<Worker> workers;
}
<小时/>
@Entity
@Getter
@Setter
@NoArgsConstructor
@AllArgsConstructor
@Table(name = "workers")
public class User extends DataAudit {
@Id
private Long id;
@ManyToOne(fetch = FetchType.LAZY)
@JoinColumn(name = "job_id", referencedColumnName = "id")
private Job job;
}
<小时/>
Worker worker1 = workerService.getWorkerById(1);
Job job = new Job(1,worker1)
jobRepo.save(job)
最佳答案
实体应该使用与 @JoinTable 的双向 OneToMany 关联:
@Entity
@Table(name = "job")
@Getter
@Setter
@NoArgsConstructor
@AllArgsConstructor
public class Job{
@Id
@Column(name = "id")
private Long id;
@OneToMany(fetch=FetchType.LAZY)
@JoinTable(name="job_workers",
joinColumns={@JoinColumn(name="job_id")},
inverseJoinColumns={@JoinColumn(name="worker_id")}
)
@Cascade(org.hibernate.annotations.CascadeType.ALL)
private Set<Worker> workers;
}
////////////////////////////////////////////////////////
@Entity
@Getter
@Setter
@NoArgsConstructor
@AllArgsConstructor
@Table(name = "workers")
public class User extends DataAudit {
@Id
private Long id;
@ManyToOne
@JoinTable(name="job_workers",
joinColumns={@JoinColumn(name="worker_id", insertable=false,updatable=false)},
inverseJoinColumns={@JoinColumn(name="job_id", insertable=false,updatable=false)})
private Job job;
}
关于java - 如何使用 Hibernate 更新实体而不是将其插入数据库?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/61381524/