我已经检查了很多相关问题，但那里的答案还没有解决我的问题。
我有通过 Hibernate 映射的实体 User 和 Character。
@Entity
@Table(name = "user", uniqueConstraints = @UniqueConstraint(columnNames = { "username" }))
public class User {
@Id
@NotEmpty
@Column(name = "username")
private String username;
...
}
@Entity
@Table(name = "character", uniqueConstraints = @UniqueConstraint(columnNames = { "charId" }))
public class Character {
...
@NotEmpty
@ManyToOne
@JoinColumn(name = "username", referencedColumnName = "username")
private User user;
...
}
我想选择具有特定用户名的所有字符，因此我使用的查询如下所示:
private final static String RETRIEVE_CHARACTERS_FOR_USER = "select c from Character as c inner join User as u where u.username = :paramUsername";
我的代码如下所示:
result = session.createQuery(RETRIEVE_CHARACTERS_FOR_USER, Character.class)
.setParameter(PARAM_USERNAME, user.getUsername()).getResultList();
我还尝试删除外键，使用String username而不是User user并只查询c.username，所以我我什至不确定问题是否与 Hibernate 有关...
希望你能帮助我! :)
最佳答案
这应该有效:
private final static String RETRIEVE_CHARACTERS_FOR_USER = "select c from Character c where c.user.username = :paramUsername";
关于java - Hibernate查询语言: Getting a SQL Syntax Error for my Query，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/61384510/