我有这个具有关系的对象:
@Entity
@Table(name = "data_model")
public class DataModel {
@Id
@GeneratedValue
@Column(name = "model_id")
private Integer id;
@Column(name = "name")
private String name;
@OneToMany(mappedBy = "dataModel", cascade = {CascadeType.PERSIST, CascadeType.REMOVE, CascadeType.MERGE})
private List<OutputField> outputFields;
}
和:
@Entity
@Table(name = "data_model_output_field")
public class OutputField {
@Id
@GeneratedValue
@Column(name = "output_field_id")
private Integer id;
@Column(name = "sourceTable")
private String sourceTable;
@JsonIgnore
@ManyToOne(optional = false, fetch = FetchType.LAZY, cascade = CascadeType.REFRESH)
@JoinColumn(name = "model_id")
private DataModel dataModel;
}
我想将此 json 反序列化为 Java 对象:
{
"name": "New data model with join",
"outputFields": [
{
"sourceTable": "r"
},
{
"sourceTable": "ri"
}
]
}
最佳答案
我解决了。我使用了 JsonManagedReference
和 JsonBackReference
注释:
@Entity
@Table(name = "data_model")
public class DataModel {
@Id
@GeneratedValue
@Column(name = "model_id")
private Integer id;
@Column(name = "name")
private String name;
@JsonManagedReference(value = "outputFields")
@OneToMany(mappedBy = "dataModel", cascade = {CascadeType.PERSIST, CascadeType.REMOVE, CascadeType.MERGE})
private List<OutputField> outputFields;
}
@Entity
@Table(name = "data_model_output_field")
public class OutputField {
@Id
@GeneratedValue
@Column(name = "output_field_id")
private Integer id;
@Column(name = "sourceTable")
private String sourceTable;
@JsonBackReference(value = "outputFields")
@ManyToOne(optional = false, fetch = FetchType.LAZY, cascade = CascadeType.REFRESH)
@JoinColumn(name = "model_id")
private DataModel dataModel;
}
关于java - 将 JAVA 对象反序列化为具有关系的 JSON,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/61479523/