我需要为石头剪刀布游戏制作一个计数器数组,但无法弄清楚如何让用户输入调用枚举,并且我需要将游戏的 Action 作为计数器,供它们使用和比较.
这是我的枚举
public enum Moves {
Rock(1),
Paper(2),
Scissors(3),
Lizard(4),
Spock(5), ;
private int countOf = 0;
private int moveVal;
private ArrayList<Moves> movesList = new ArrayList<>();
Moves(int moveVal) {
}
public int getmoveVal() {
return moveVal;
}
public int getCountOf() {
for(Moves moveList : Moves.values()) {
countOf++;
}
return countOf;
}
这是我的类(class),会调用它
public static void main(String[] args) {
RockPaperScissorGame rsg = new RockPaperScissorGame(3);
Moves move[] = Moves.values();
int playerMove = 0;
for(int i = 0; i < move.length; i++) {
}
boolean continueGame = true;
@SuppressWarnings("resource")
Scanner keyboard = new Scanner(System.in);
while(continueGame)
{
System.out.println(rsg.moveChoices());
System.out.println("Enter Move:(1,2,3,4 or 5):");
playerMove = keyboard.nextInt();
rsg.playRound(move);
System.out.printf("AI %s!%n", rsg.getAIOutcome().toString());
System.out.printf("Player %s!%n", rsg.getPlayerOutcome().toString());
System.out.println(rsg.moveOutcome());
System.out.println(rsg.currentScore());
if(rsg.isGameOver())
{
System.out.println(rsg.currentWinTotal());
System.out.println("Do you want to Play Again(1 - Yes , 2 - No):");
int answer = keyboard.nextInt();
if(answer == 2)
{
continueGame = false;
}
else
{
rsg.reset();
}
}
}
最佳答案
您可以遍历values
来查找与moveVal
匹配的Move
:
public Move fromMoveVal(int moveVal) {
for (Move m : Move.values()) if (m.moveVal == moveVal) return m;
return null;
}
关于java - 需要使用枚举序数创建一个计数器,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/61601593/