java - 连续求和用户输入 - JAVA

Question

需要帮助对连续用户输入进行求和，直到输入 0。已经很接近了。只需要知道我缺少什么。 下面是代码

import java.util.Scanner;

public class Task3 {

    public static void main(String[] args) {
        while (true) {
            Scanner in = new Scanner(System.in);
            System.out.println("Enter a number");
            int number = in.nextInt();
            if (number == 0) {
                System.out.println("Okay thanks!");
                break;
            } else {
                System.out.println("The current answer is :" + number);
            }
        }

    }

}

Answer 1

解决代码中的以下问题:

1. 您绝不能在循环内实例化 Scanner。
2. 您需要一个变量，例如sum 存储数字的运行总和。

按如下方式进行:

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int sum = 0;
        while (true) {
            System.out.print("Enter a number (0 to quit): ");
            int number = in.nextInt();
            if (number == 0) {
                System.out.println("Okay thanks!");
                break;
            }
            sum += number;
        }
        System.out.println("Sum of numbers = " + sum);
    }
}

示例运行:

Enter a number (0 to quit): 10
Enter a number (0 to quit): 20
Enter a number (0 to quit): 30
Enter a number (0 to quit): 0
Okay thanks!
Sum of numbers = 60