我有一个矩阵(具有 class
character
的值,如下所示:
mat <- matrix(c("0", "TRUE", "1", "2",
"FALSE", "TRUE", "TRUE", "2"), nrow = 4, ncol = 2)
#> mat
# [,1] [,2]
#[1,] "0" "FALSE"
#[2,] "TRUE" "TRUE"
#[3,] "1" "TRUE"
#[4,] "2" "2"
我需要将其转换为这样的矩阵:
[,1] [,2]
[1,] FALSE FALSE
[2,] TRUE TRUE
[3,] TRUE TRUE
[4,] TRUE TRUE
as.logic
将 NA
输出为“字符数字”值,而 as.numeric
输出 NA
>s 为“字符逻辑”值。
我找到了一个解决方案,但我认为我缺少一些关于立即转换的明显信息:
new_mat2 <- array(as.numeric(mat), dim(mat))
new_mat <- array(as.logical(mat), dim(mat))
new_mat[is.na(new_mat)] <- new_mat2[is.na(new_mat)]
mat2 <- array(as.logical(new_mat), dim(new_mat))
#> mat2
# [,1] [,2]
#[1,] FALSE FALSE
#[2,] TRUE TRUE
#[3,] TRUE TRUE
#[4,] TRUE TRUE
有什么建议吗?
最佳答案
试试这个:
> mat[,] <- ifelse(mat %in% c("0", "FALSE"), FALSE, TRUE) # pay attention to @Señor O comment to shorten this step.
> mat
[,1] [,2]
[1,] "FALSE" "FALSE"
[2,] "TRUE" "TRUE"
[3,] "TRUE" "TRUE"
[4,] "TRUE" "TRUE"
如果您希望 mat
成为由逻辑值组成的 data.frame,则:
> mat <- sapply(as.data.frame(mat), as.logical)
> mat
V1 V2
[1,] FALSE FALSE
[2,] TRUE TRUE
[3,] TRUE TRUE
[4,] TRUE TRUE
> sapply(mat, class) # checking class
[1] "logical" "logical" "logical" "logical" "logical" "logical" "logical" "logical"
关于r - 将 "character"矩阵转换为 "logical",我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/19569391/