我在请求 Web 服务期间遇到错误。
我使用了 Spring boot 3.x
<plugin>
<groupId>org.codehaus.mojo</groupId>
<artifactId>jaxb2-maven-plugin</artifactId>
<version>2.5.0</version>
<executions>
<execution>
<id>apps</id>
<goals>
<goal>xjc</goal>
</goals>
<configuration>
<target>2.1</target>
<episodeFileName>episode_apps</episodeFileName>
<xjbSources>
<xjbSource>src/main/resources/appstms.xjb</xjbSource>
</xjbSources>
<sources>
<source>src/main/resources/xsd/schema-apps.xsd</source>
</sources>
<outputDirectory>${basedir}/src/main/java</outputDirectory>
<!--
<outputDirectory>
${project.parent.relativePath}/src/main/java/by/*/reception/electronic/docs/service/
</outputDirectory>-->
<packageName>*.reception.electronic.docs.service.generated.xml.entrypoint</packageName>
<!-- <outputDirectory>*.reception.electronic.docs.service.generate
</outputDirectory>-->
<clearOutputDir>false</clearOutputDir>
</configuration>
</execution>
</executions>
</plugin>
- 配置
@EnableWs
@Configuration
public class WebServiceConfig {
private static final String NAMESPACE_URI = "http://*.com/apps";
@SuppressWarnings({"rawtypes", "unchecked"})
@Bean(name = "apsMessage")
public ServletRegistrationBean messageDispatcherServlet(ApplicationContext appContext){
MessageDispatcherServlet servlet = new MessageDispatcherServlet();
servlet.setApplicationContext(appContext);
servlet.setTransformWsdlLocations(true);
return new ServletRegistrationBean(servlet, "/ws/*");
}
@Bean
public SaajSoapMessageFactory messageFactory() {
SaajSoapMessageFactory messageFactory = new SaajSoapMessageFactory();
messageFactory.setSoapVersion(SoapVersion.SOAP_12);
return messageFactory;
}
/* localhost:8080/ws/appsTms.wsdl
* */
@Bean(name = "appsTms")
public DefaultWsdl11Definition defaultWsdl11Definition(@Qualifier("appsTmsSchema") XsdSchema schema){
DefaultWsdl11Definition wsdl11Definition = new DefaultWsdl11Definition();
wsdl11Definition.setPortTypeName("ApsPort");
wsdl11Definition.setLocationUri("/ws");
wsdl11Definition.setTargetNamespace(NAMESPACE_URI);
wsdl11Definition.setSchema(schema);
wsdl11Definition.setCreateSoap11Binding(true);
wsdl11Definition.setCreateSoap12Binding(true);
return wsdl11Definition;
}
@Bean(name = "appsTmsSchema")
public XsdSchema moviesSchema(){
return new SimpleXsdSchema(new ClassPathResource("xsd/schema-apps.xsd"));
}
}
- 和端点
@Endpoint
public class MessageEndpoint {
private static final Logger LOGGER = LoggerFactory.getLogger( MessageEndpoint.class );
private static final String NAMESPACE_URI = "http://*.com";
@PayloadRoot(namespace = NAMESPACE_URI, localPart = "Multiply")
@ResponsePayload
public MultiplyResponse getMultiplyResponse(@RequestPayload Multiply messageRequest) throws Exception {
String fileName1 = messageRequest.getFileName1();
System.out.println(fileName1);
MultiplyResponse response = new MultiplyResponse();
response.setReturn("");
return response;
}
}
当我尝试执行查询并传递 Xml 时,我什至没有到达 Web 服务端点所在的类。
我有一个错误:
08-06-2020 16:44:27.935 INFO 14660
o.s.web.servlet.DispatcherServlet : Initializing Servlet 'dispatcherServlet'XML-22103: (Fatal Error) DOMResult can not be this kind of node. 08-06-2020 16:44:27.936 DEBUG 14660
o.s.web.servlet.DispatcherServlet : Detected StandardServletMultipartResolver 08-06-2020 16:44:27.951 DEBUG 14660 o.s.web.servlet.DispatcherServlet : enableLoggingRequestDetails='false': request parameters and headers will be masked to prevent unsafe logging of potentially sensitive data 08-06-2020 16:44:27.951 INFO 14660
o.s.web.servlet.DispatcherServlet : Completed initialization in 15 ms 08-06-2020 16:44:27.952 DEBUG 14660
o.s.web.servlet.DispatcherServlet : "ERROR" dispatch for POST "/error", parameters={} 08-06-2020 16:44:27.955 DEBUG 14660
s.w.s.m.m.a.RequestMappingHandlerMapping : Mapped to org.springframework.boot.autoconfigure.web.servlet.error.BasicErrorController#error(HttpServletRequest) 08-06-2020 16:44:27.976 DEBUG 14660
o.s.w.s.m.m.a.HttpEntityMethodProcessor : Using 'application/json', given [/] and supported [application/json, application/+json, application/json, application/+json] 08-06-2020 16:44:27.976 DEBUG 14660 o.s.w.s.m.m.a.HttpEntityMethodProcessor : Writing [{timestamp=Mon Jun 08 16:44:27 MSK 2020, status=500, error=Internal Server Error, message=, path=/ws (truncated)...] 08-06-2020 16:44:28.004 DEBUG 14660 o.s.web.servlet.DispatcherServlet : Exiting from "ERROR" dispatch, status 500
知道这是什么以及如何解决它吗?
最佳答案
原因如下:
相邻系统由自己的 xsd 工作,并具有与发送到 Web 服务的文档进行映射的命名空间 uri。
相邻系统是一个中介者,接收 xml 文档并发送到另一个系统进行处理。
首先,她查找 到 中,并且比她想象的要多,在 Web 服务(soap)中的端点特定命名空间,指向 xsd ,基于WSDL构建。
adjiong 系统可以使用:
<?xml version="1.0" encoding="UTF-8"?>
<xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema"
xmlns:tns="http://ws.transit.ls.com"
targetNamespace="http://ws.transit.ls.com"
elementFormDefault="qualified">
<xs:element name="Multiply">
....
- 注意:targetNamespace="http://ws.transit.ls.com "
您必须将这样的targetNamespace指向:
@Endpoint
public class MessageEndpoint {
private static final Logger LOGGER = LoggerFactory.getLogger( MessageEndpoint.class );
private static final String NAMESPACE_URI = "http://ws.transit.ls.com";
@PayloadRoot(namespace = NAMESPACE_URI, localPart = "Multiply")
@ResponsePayload
public MultiplyResponse getMultiplyResponse(@RequestPayload Multiply messageRequest) throws Exception {
String fileName = messageRequest.getFileName1();
...
您还必须使用能够连接系统运行的 xsd(不得对 xsd 进行任何更改)
如果您正在创建新的 Web 服务 Soap,并首先创建一个应用程序,其他客户端将粘附您的 xsd。
但就我而言,我必须遵守禁止系统的规则。
关于java - XML-22103 : (Fatal Error) DOMResult can not be this kind of node,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/62263743/