我想在任何应用程序的特定时间弹出对话框我的代码:
public class testPOPDialog extends Activity {
/** Called when the activity is first created. */
private Handler mHandler = new Handler();
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
mHandler.postDelayed(mUpdateTimeTask, 1000);
}
private Runnable mUpdateTimeTask = new Runnable() {
public void run() {
AlertDialog d = new AlertDialog.Builder(testPOPDialog.this)
.setTitle("tanchulai")
.setMessage("bucuo de tanchulai")
.create();
d.getWindow().setType(WindowManager.LayoutParams.TYPE_SYSTEM_ALERT);
d.show();
}
};
}
它给我
12-03 10:12:18.162: ERROR/AndroidRuntime(571): android.view.WindowManager$BadTokenException: Unable to add window android.view.ViewRoot$W@43dd71c0 -- permission denied for this window type
这是什么权限
如果我删除 d.getWindow().setType(WindowManager.LayoutParams.TYPE_SYSTEM_ALERT);
我的应用是正确的......
最佳答案
将此权限添加到您的 list 中:
android.permission.SYSTEM_ALERT_WINDOW
关于android - 任何应用程序中的弹出窗口,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/4344523/