java - 如何将参数传递给 Hibernate 的 subselect 标签？

Question

hibernate section 5.1.3末尾的示例没有显示传递参数的示例。

There is no difference between a view and a base table for a Hibernate mapping. This is transparent at the database level, although some DBMS do not support views properly, especially with updates. Sometimes you want to use a view, but you cannot create one in the database (i.e. with a legacy schema). In this case, you can map an immutable and read-only entity to a given SQL subselect expression:

<class name="Summary">
    <subselect>
        select item.name, max(bid.amount), count(*)
        from item
        join bid on bid.item_id = item.id
        group by item.name
    </subselect>
    <synchronize table="item"/>
    <synchronize table="bid"/>
    <id name="name"/>
    ...
</class>

这可能吗？如果是这样，怎么办？

谢谢， 弗兰兹

Answer 1

我认为这是不可能的，因为映射文件就像一个静态描述。