java.util.regex.PatternSyntaxException : null (in java. util.regex.Pattern)错误

Question

public void convertStrings() {
    for (int counter = 0; counter < compare.length; counter++) {
            compare[counter] = compare[counter].replace('*','_'); 
            compare[counter] = compare[counter].replaceAll("_",".*"); 
            compare[counter] = compare[counter].replace('?', '.'); 
    }
    // System.out.printf("%s", Arrays.toString(compare));
} 
public void compareStrings() {
    for (int counter = 0; counter < data.length; counter++) {
        for (int counter1 = 0; counter1 < compare.length; counter1++) {

            if (data[counter].matches(compare[counter1]) == true) {
                System.out.printf("%s ", data[counter]); 
            }

        }
        System.out.println(); 
    }
}

}

我想做的是将输入中的任何 * 替换为 .* ，这样当我将字符串与之前的任何内容进行比较时，它会忽略以前的字符。另外，我正在转换一个“？”转换为占位符值“.”。但是，当我运行编译后的代码时，我收到此错误，因为字符串将特殊字符转换为常规字母。如何让编译器注册这些特殊字符来执行该功能？

Answer 1

只需将行更改为:

compare[counter] = compare[counter].replaceAll("\\*",".*").replaceAll("\\?", ".");