java - 浮桥游戏迷失在代码中

Question

所以事情就是这样。我开始研究简单的java编程。并达到了涵盖所有简单类(class)的程度，并且已经知道如何进行一些简单的编码。我遇到的麻烦是在一个代码中使用我所涵盖的所有知识。我想创建一个游戏，因为我被告知这是可能的，我认为他们是在 Java 的实际类(class)上做的。虽然我遇到了一些问题。它正在工作，但当玩家的手牌上升超过 24 点时，它不会停止。在游戏中，玩家应该在什么地方破产，它不断询问你是否想要另一张卡？我已经使用了 if 语句，但它似乎没有注意到它。

import java.util.Scanner;

public class Pontoon{

 public static void main(String[] args) {
    Scanner input = new Scanner(System.in);
    int playerScore = 0, computerScore = 0;
    String newCard = "";
    playerScore += dealCard();
    computerScore += dealCard();
    playerScore += dealCard();
    computerScore += dealCard();

    System.out.printf("Your score is %d would you like another card ? y/n ", playerScore);
    newCard = input.nextLine();
    if(newCard.equalsIgnoreCase("Y")) {
        while (newCard.equalsIgnoreCase("Y") && playerScore < 21) { 
            playerScore += dealCard();
            System.out.printf("Your score is %d would you like another card ? y/n ", playerScore);
            newCard = input.nextLine();
        }
    }
    while(computerScore < 15){
        computerScore += dealCard();
    }
    checkWin(playerScore, computerScore);
}
public static int dealCard(){
    int value = (int) (Math.random() * 13) + 1;
    int score = 0;
    if(value == 1) {
        System.out.println("Ace!");
        score = 11;
    }else if (value == 13) {
        System.out.println("King!");
        score = 10;
    }else if (value == 12) {
        System.out.println("Queen!");
        score = 10;
    } else if (value == 11) {
        System.out.println("Jack!");
        score = 10;
    } else {
        score = value;
    }

    return score;
}

public static void checkWin(int Player, int Computer) {
    int player = Player;
    int computer = Computer;

    if (player > 21) {
        System.out.println("Player Bust");
    } else if (computer > 21) {
        System.out.println("Computer Bust");
    } else {
        if (player > computer) {
            System.out.println("Player Wins!");
        } else {
            System.out.println("Computer Wins!");
        }
    }
}
}

Answer 1

在 while 循环中:

while (newCard.equalsIgnoreCase("Y")) { 

添加一个条件来检查玩家得分

while (newCard.equalsIgnoreCase("Y") && playerScore < 21) {