我在 Java Web 应用程序中收到以下代码的错误--
XStream xstream = new XStream();
apiresponse myClassObject;
myClassObject= xstream.fromXML(resp);
此行上方的代码行显示错误 - error="类型不匹配 - 无法从对象转换为 apiresponse"
下面给出的是我必须解析的 XML---
<apiresponse version="1" xmlns="http://ahrefs.com/schemas/api/links/1">
<resultset_links count="2">
<result>
<source_url>http://ahrefs.com/robot/</source_url>
<destination_url>http://blog.ahrefs.com/</destination_url>
<source_ip>50.22.24.236</source_ip>
<source_title>Ahrefs – backlinks research tool</source_title>
<visited>2011-08-31T07:56:53Z</visited>
<anchor>Blog</anchor>
<rating>257.674000</rating>
<link_type>text</link_type>
<is_nofollow>false</is_nofollow>
</result>
<result>
<source_url>http://apps.vc/</source_url>
<destination_url>http://ahrefs.com/robot/</destination_url>
<source_ip>64.20.55.86</source_ip>
<source_title>Device info</source_title>
<visited>2011-08-27T18:59:31Z</visited>
<anchor>http://ahrefs.com/robot/</anchor>
<rating>209.787100</rating>
<link_type>text</link_type>
<is_nofollow>false</is_nofollow>
</result>
</resultset_links>
</apiresponse>
我创建了以下java类来从上面的xml获取数据---
package com.arvindikchari.linkdatasmith.domain;
final public class apiresponse {
protected resultset_links rlinks;
public apiresponse() {
}
public resultset_links getRlinks()
{
return rlinks;
}
public setRlinks(resultset_links rlinks)
{
this.rlinks=rlinks;
}
}
final public class resultset_links {
protected List<result> indiv_result = new ArrayList<result>();
public resultset_links() {
}
public List<result> getIndiv_result()
{
return List;
}
public void setIndiv_result(List<result> indiv_result)
{
this.indiv_result=indiv_result;
}
}
final public class result {
protected String source_url;
protected String destination_url;
protected String source_ip;
protected String source_title;
protected String visited;
protected String anchor;
protected String rating;
protected String link_type;
public result() {
}
public String getSource_url()
{
return source_url;
}
public void setSource_url(String source_url)
{
this.source_url=source_url;
}
public String getDestination_url()
{
return destination_url;
}
public void setDestination_url(String destination_url)
{
this.destination_url=destination_url;
}
public String getSource_ip()
{
return source_ip;
}
public void setSource_ip(String source_ip)
{
this.source_ip=source_ip;
}
public String getSource_title()
{
return source_title;
}
public void setSource_title(String source_title)
{
this.source_title=source_title;
}
public String getVisited()
{
return visited;
}
public void setVisited(String visited)
{
this.visited=visited;
}
public String getAnchor()
{
return anchor;
}
public void setAnchor(String anchor)
{
this.anchor=anchor;
}
public String getRating()
{
return rating;
}
public void setRating(String rating)
{
this.rating=rating;
}
public String getLink_type()
{
return link_type;
}
public void setLink_type(String link_type)
{
this.link_type=link_type;
}
}
我在这里做错了什么？
最佳答案
您有很多错误，但与您的消息相对应的错误是您必须将 xstream.fromXML 的结果转换为 apiresponse' 对象:
apiresponse result = (apiresponse)xstream.fromXML(resp);
此外，您提供的代码(Java类)无法编译，有很多错误。
以下是一些改进:
Result.java:
@XStreamAlias("result")
public class Result {
protected String source_url;
protected String destination_url;
protected String source_ip;
protected String source_title;
protected String visited;
protected String anchor;
protected String rating;
protected String link_type;
protected Boolean is_nofollow;
public Result() {
}
public String getSource_url()
{
return source_url;
}
public void setSource_url(String source_url)
{
this.source_url=source_url;
}
public String getDestination_url()
{
return destination_url;
}
public void setDestination_url(String destination_url)
{
this.destination_url=destination_url;
}
public String getSource_ip()
{
return source_ip;
}
public void setSource_ip(String source_ip)
{
this.source_ip=source_ip;
}
public String getSource_title()
{
return source_title;
}
public void setSource_title(String source_title)
{
this.source_title=source_title;
}
public String getVisited()
{
return visited;
}
public void setVisited(String visited)
{
this.visited=visited;
}
public String getAnchor()
{
return anchor;
}
public void setAnchor(String anchor)
{
this.anchor=anchor;
}
public String getRating()
{
return rating;
}
public void setRating(String rating)
{
this.rating=rating;
}
public String getLink_type()
{
return link_type;
}
public void setLink_type(String link_type)
{
this.link_type=link_type;
}
public Boolean getIs_nofollow() {
return is_nofollow;
}
public void setIs_nofollow(Boolean is_nofollow) {
this.is_nofollow = is_nofollow;
}
ResultsetLinks.java:
@XStreamAlias("resultset_links")
public class ResultsetLinks {
@XStreamImplicit(itemFieldName="result")
protected List<Result> indivResult = new ArrayList<Result>();
public ResultsetLinks() {
}
public List<Result> getResult()
{
return indivResult;
}
public void setResult(List<Result> indiv_result)
{
this.indivResult =indiv_result;
}
}
ApiResponse.java:
@XStreamAlias("apiresponse")
public class ApiResponse {
@XStreamAlias("resultset_links")
protected ResultsetLinks rlinks;
public ApiResponse() {
}
public ResultsetLinks getRlinks()
{
return rlinks;
}
public void setRlinks(ResultsetLinks rlinks)
{
this.rlinks=rlinks;
}
}
最后是解码 XML 的代码:
XStream xstream = new XStream();
xstream.processAnnotations(ApiResponse.class);
xstream.processAnnotations(ResultsetLinks.class);
xstream.processAnnotations(Result.class);
ApiResponse result = (ApiResponse)xstream.fromXML(resp);
所有这些代码都可以在 Xstream 1.4.2 上正常工作
尝试遵循 Sun 的类名称、属性名称等编码约定... 使用 XstreamAliases 使 Java 类名适应 XML 名称。
关于java-当我尝试使用 xstream 将 xml 响应转换为 pojo 时出错，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/8518220/