我获取枚举值作为输入,每个枚举值对应于一个类。 如何定义 spring 配置给定的枚举值应转换为类对象
public enum R {
eR1,
eR2,
eR3;
}
//simple interface
interface R {
dosomething();
}
//R1 class
class R1 implements R {
dosomething() {
//implmentation for R1
}
}
//R2 class
class R2 implements R {
dosomething() {
//implementation for R2
}
}
我有 API 说,
getR(R er1) {
//How do I define spring configuration to get class object given enum value??
}
I want to avoid if conditions in API, something like this
getR(R er) {
if(er.equals(R.eR1)) {
//do this
} else if(er.equals(R.eR2)) {
//do this
}
}
I want to spring to inject right class based on input parameter so that I can avoid if statement.
假设对于三个枚举字段,我想避免在 spring 中拥有三个 id。
Can I define somethign like this
<bean id="r" class="com.myProject.R1">
<property name="er1" value="eR1"/>
</bean>
<bean id="r" class="com.myProject.R2">
<property name="er2" value="eR2"/>
</bean>
//similary for R3 as well
最佳答案
在你的 spring 配置中只需使用枚举值
示例如果你想将 eR2 注入(inject) R2 内,
<bean id="r2" class="com.myProject.R2">
<property name="er2" value="eR2"/>
</bean>
查看示例 here 。您无需使用完全限定名称。请参阅 How assign bean's property an Enum value in Spring config file? 上的讨论.
关于java - 枚举到类对象的转换,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/8817263/