java - 如何一次只允许 3 个中的 1 个 android 切换按钮打开

Question

我正在使用 3 个切换按钮。在我的 android 应用程序中，我希望一次只能选择这些切换按钮中的 1 个。我该怎么做呢？

Answer 1

一个简单的 onChangeListener 就可以:

public class TestProjectActivity extends Activity {

ToggleButton one; 
ToggleButton two;
ToggleButton three;
ToggleButton four;

/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);


    one = (ToggleButton) findViewById(R.id.toggleButton1);
    two = (ToggleButton) findViewById(R.id.toggleButton2);
    three = (ToggleButton) findViewById(R.id.toggleButton3);
    four = (ToggleButton) findViewById(R.id.toggleButton4);

    one.setOnCheckedChangeListener(changeChecker);
    two.setOnCheckedChangeListener(changeChecker);
    three.setOnCheckedChangeListener(changeChecker);
    four.setOnCheckedChangeListener(changeChecker);
}

OnCheckedChangeListener changeChecker = new OnCheckedChangeListener() {

    @Override
    public void onCheckedChanged(CompoundButton buttonView, boolean isChecked) {
        if (isChecked){
            if (buttonView == one) {
                two.setChecked(false);
                three.setChecked(false);
                four.setChecked(false);
            }
            if (buttonView == two) {
                one.setChecked(false);
                three.setChecked(false);
                four.setChecked(false);
            }
            if (buttonView == three) {
                two.setChecked(false);
                one.setChecked(false);
                four.setChecked(false);
            }
            if (buttonView == four) {
                two.setChecked(false);
                three.setChecked(false);
                one.setChecked(false);
            }
        }
    }
};

}