我正在为 Android 开发一款问答游戏。生成一个随机数来随机选择一个问题。当我到达嵌套 switch 语句时，Eclipse 会从这部分给出错误“v 无法解析”:
switch(v.getId()) {
case R.id.button0:
Toast.makeText(BeginGame.this, "success",Toast.LENGTH_SHORT).show();<br/>
break;
default:
Toast.makeText(BeginGame.this,"Fail",Toast.LENGTH_SHORT).show();<br/>
break;
有什么建议吗？
`公共(public)类 BeginGame 扩展 Activity {
public OnTouchListener nextListener = new OnTouchListener() {
@Override
public boolean onTouch(View v, MotionEvent event) {
if (event.getAction() == MotionEvent.ACTION_DOWN) {
Log.d("base", "next");
}
return false;
}
};
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main2);
int[] questionArray = {-1,-1,-1,-1,-1,-1,-1};
Random questionNumberGenerated = new Random();
int num;
boolean duplicate = false;
do{
num = questionNumberGenerated.nextInt(7);
for (int i=0; i<questionArray.length; i++){
if (num == questionArray[i]){
duplicate=true;
}
}
}while (duplicate);
if (duplicate=false){
for (int j=0; j<questionArray.length; j++)
questionArray[j]=num;
}
switch (num) {
case 0:
Button button0 = (Button) findViewById(R.id.button0);
button0.setOnTouchListener(nextListener);
Button button1 = (Button) findViewById(R.id.button1);
button1.setOnTouchListener(nextListener);
Button button2 = (Button) findViewById(R.id.button2);
button2.setOnTouchListener(nextListener);
Button button3 = (Button) findViewById(R.id.button3);
button3.setOnTouchListener(nextListener);
TextView text = (TextView) findViewById(R.id.TextView01);
text.setText("press alabama:");
button0.setText("Alabama");
button1.setText("Mississippi");
button2.setText("Philadelphia");
button3.setText("Virginia");
switch(v.getId()) {
case R.id.button0:
Toast.makeText(BeginGame.this, "success", Toast.LENGTH_SHORT).show();
break;
default:
Toast.makeText(BeginGame.this, "Fail", Toast.LENGTH_SHORT).show();
break;
}
case 1:
text.setText("press green");
button0.setText("zsx");
button1.setText("zczcz");
button2.setText("zczc");
button3.setText("green");
case 2:
text.setText("press blue");
button0.setText("www");
button1.setText("aaa");
button2.setText("dddd");
button3.setText("blue");
case 3:
text.setText("press red");
button0.setText("111");
button1.setText("222");
button2.setText("3333");
button3.setText("red");
}
}
}
`
最佳答案
你到底想做什么？该方法中没有 v 的定义。 如果您想在按钮触摸上执行某些任务，请将开关盒移动到 onTouch 方法，如下所示。
public boolean onTouch(View v, MotionEvent event) {
switch(v.getId()) {
case R.id.button0:
Toast.makeText(BeginGame.this, "success", Toast.LENGTH_SHORT).show();
break;
default:
Toast.makeText(BeginGame.this, "Fail", Toast.LENGTH_SHORT).show();
break;
}
}
关于java - Android onTouchListener 不适用于嵌套 switch 语句，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/9272011/