所以我必须实现纸牌游戏 war 。我一切都很顺利，除了当循环达到其中一张牌(数组列表)的大小时停止之外。我想要它做的是循环，直到其中一张牌是空的。并指导我如何做到这一点？我知道我的代码可以缩短，但我现在不需要担心这一点。这是我的代码:
import java.util.*;
import java.lang.*;
public class lab9_11{
public static void main(String args[]){
System.out.printf("\n");
System.out.printf("\n");
System.out.printf("\\ / /\\ |\\ |\n");
System.out.printf(" \\ / \\ / /__\\ |/ |\n");
System.out.printf(" \\/ \\/ / \\ |\\ o\n");
System.out.printf("\n");
System.out.printf("Lets play a game of war.\n");
System.out.printf("Type 1 to begin or 0 to exit.\n");
Scanner keyboard = new Scanner(System.in);
int initial = keyboard.nextInt();
if (initial > 1){
System.out.printf("You can't read, so you shouldn't play this.\n");
System.exit(-1);
}
if (initial == 0){
System.exit(-1);
}
else {
System.out.printf("Okay, lets play!\n");
System.out.printf("\n");
}
System.out.printf("Here is a deck of 52 cards -> []:\n");
int deck[] = new int[52];
deck[0] = 2; //0-12 = hearts
deck[1] = 3;
deck[2] = 4;
deck[3] = 5;
deck[4] = 6;
deck[5] = 7;
deck[6] = 8;
deck[7] = 9;
deck[8] = 10;
deck[9] = 11; //jack of hearts
deck[10] = 12; //queen of hearts
deck[11] = 13; //king of hearts
deck[12] = 14; //ace of hearts
deck[13] = 2; //13-25 = spades
deck[14] = 3;
deck[15] = 4;
deck[16] = 5;
deck[17] = 6;
deck[18] = 7;
deck[19] = 8;
deck[20] = 9;
deck[21] = 10;
deck[22] = 11; //jack of spades
deck[23] = 12; //queen of spades
deck[24] = 13; //king of spades
deck[25] = 14; //ace of spades
deck[26] = 2; //0-12 = diamonds
deck[27] = 3;
deck[28] = 4;
deck[29] = 5;
deck[30] = 6;
deck[31] = 7;
deck[32] = 8;
deck[33] = 9;
deck[34] = 10;
deck[35] = 11; //jack of diamonds
deck[36] = 12; //queen of diamonds
deck[37] = 13; //king of diamonds
deck[38] = 14; //ace of diamonds
deck[39] = 2; //39-51 = clubs
deck[40] = 3;
deck[41] = 4;
deck[42] = 5;
deck[43] = 6;
deck[44] = 7;
deck[45] = 8;
deck[46] = 9;
deck[47] = 10;
deck[48] = 11; //jack of clubs
deck[49] = 12; //queen of clubs
deck[50] = 13; //king of clubs
deck[51] = 14; //ace of clubs
System.out.printf("First, lets shuffle it into 2 decks of 26.\n");
Random rangen = new Random(); //Random number generator
for (int i=0; i < deck.length; i++) { //shuffles the deck
int randomPosition = rangen.nextInt(deck.length);
int temp = deck[i];
deck[i] = deck[randomPosition];
deck[randomPosition] = temp;
}
int[] player1 = new int[26]; //initializes 1st player's deck
int[] player2 = new int[26]; //initializes 2nd player's deck
System.arraycopy(deck, 0, player1, 0, player1.length); //takes 26 cards and puts into player1's deck.
System.arraycopy(deck, player1.length, player2, 0, player2.length);//takes the other 26 and puts into player2's deck.
System.out.printf(".\n");
System.out.printf(".\n");
System.out.printf("Here's your deck. --> [?]\n");
System.out.printf(".\n");
System.out.printf(".\n");
System.out.printf("Here's your opponent's deck. --> [?]\n");
System.out.printf(".\n");
System.out.printf(".\n");
System.out.printf("Okay, lets begin!\n");
System.out.printf("\n");
System.out.printf("\n");
System.out.printf("Type 1 to flip your cards.\n");
System.out.printf("Which ever player holds all the cards by the end wins.\n");
int q = keyboard.nextInt();
if (q == 1){
System.out.printf("Lets see...\n");
}
if (q != 1){
System.out.printf("That wasn't one... type the number '1' or else the game will end because you are stupid.\n");
int q2 = keyboard.nextInt();
if (q != 1) {
System.exit(-1);
}
}
List<Integer> player1List = new ArrayList<Integer>();//converts array1 into arraylist1
for (int i = 0; i < player1.length; i++)
{
player1List.add(player1[i]);
}
System.out.println(player1List);
List<Integer> player2List = new ArrayList<Integer>();//converts array2 into arraylist2
for (int i = 0; i < player2.length; i++)
{
player2List.add(player2[i]);
}
System.out.println(player2List);
for (int i = 0; i < player1List.size(); i++){
if (player1List.get(i) < player2List.get(i)){
System.out.printf("Player 1: %d\n", player1List.get(i));
System.out.printf("Player 2: %d\n", player2List.get(i));
System.out.printf("Player 2 wins round!\n");
player2List.add(player1List.get(i));
player1List.remove(player1List.get(i));
}
if (player1List.get(i) < player2List.get(i)){
System.out.printf("Player 1: %d\n", player1List.get(i));
System.out.printf("Player 2: %d\n", player2List.get(i));
System.out.printf("Player 1 wins round!\n");
player1List.add(player2List.get(i));
player2List.remove(player2List.get(i));
}
if (player1List.get(i) == player2List.get(i)){
System.out.printf("Player 1: %d\n", player1List.get(i));
System.out.printf("Player 2: %d\n", player2List.get(i));
System.out.printf("It's a tie, cards return to your deck.\n");
}
}
if (player1List.isEmpty() || player2List.isEmpty()){
if (player1List.isEmpty()) {
System.out.printf("Player 2 WINS THE GAME!!!!!!\n");
}
if (player2List.isEmpty()) {
System.out.printf("Player 1 WINS THE GAME!!!!!!\n");
}
}
System.out.println(player1List);
System.out.println(player2List);
/*
System.out.printf("test.\n");
System.out.printf("test1111.\n");
for(int i = 0; i < player1.length; i++){
System.out.println(player1[i]);
}
System.out.printf("test.\n");
System.out.printf("test222.\n");
for(int i = 0; i < player2.length; i++){
System.out.println(player2[i]);
}
System.out.printf("test.\n");
System.out.printf("test11.\n");
for(int i = 0; i < win1.length; i++){
System.out.println(win1[i]);
}
System.out.printf("test.\n");
System.out.printf("test22.\n");
for(int i = 0; i < win2.length; i++){
System.out.println(win2[i]);
}
*/
System.out.printf("\n");
System.out.printf("\n");
}
}
这是我缩小范围的 for 循环。我需要它，因此它会循环直到其中一个数组列表为空。
for (int i = 0; i < player1List.size(); i++){
if (player1List.get(i) < player2List.get(i)){
System.out.printf("Player 1: %d\n", player1List.get(i));
System.out.printf("Player 2: %d\n", player2List.get(i));
System.out.printf("Player 2 wins round!\n");
player2List.add(player1List.get(i));
player1List.remove(player1List.get(i));
}
if (player1List.get(i) < player2List.get(i)){
System.out.printf("Player 1: %d\n", player1List.get(i));
System.out.printf("Player 2: %d\n", player2List.get(i));
System.out.printf("Player 1 wins round!\n");
player1List.add(player2List.get(i));
player2List.remove(player2List.get(i));
}
if (player1List.get(i) == player2List.get(i)){
System.out.printf("Player 1: %d\n", player1List.get(i));
System.out.printf("Player 2: %d\n", player2List.get(i));
System.out.printf("It's a tie, cards return to your deck.\n");
}
}
if (player1List.isEmpty() || player2List.isEmpty()){
if (player1List.isEmpty()) {
System.out.printf("Player 2 WINS THE GAME!!!!!!\n");
}
if (player2List.isEmpty()) {
System.out.printf("Player 1 WINS THE GAME!!!!!!\n");
}
}
最佳答案
我建议使用 Queue对于您的牌组，因为您需要将(提供)牌放在牌组的一侧(底部)并从顶部(直到我从维基百科条目中了解到有关此游戏的信息)。 LinkedList 是Queue 的一个很好的实现。代码可以是这样的:
while(!deck1.isEmpty() && !deck2.isEmpty()) {
int card1 = deck1.poll();
int card2 = deck2.poll();
if(card1 < card2) {
deck2.offer(card2);
deck2.offer(card1);
}
if(card2 < card1) {
deck1.offer(card1);
deck1.offer(card2);
}
if(card1 == card2) {
deck1.offer(card1);
deck2.offer(card2);
}
}
关于Java纸牌游戏。 ( war 游戏)，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/9764525/