java - 时间戳格式匹配

Question

我编写了这段代码用于将字符串转换为时间戳:

String timeStamp = "2012-04-13 09:00:30";

    try{

        SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
        java.util.Date parsedDate = sdf.parse(timeStamp);
        System.out.println(parsedDate.toString());
        java.sql.Timestamp timestamp = new java.sql.Timestamp(parsedDate.getTime());
        System.out.println(timestamp.toString());           

    }catch (Exception e) {
        // TODO: handle exception
    }

我得到的输出是:

2012-04-13 09:00:30.0

但我希望输出是:

2012-04-13 09:00:30

即我不需要末尾的 .0

请提出建议

谢谢

Answer 1

您需要使用SimpleDateFormat的format()方法

    SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
    //parsing string to date
    java.util.Date parsedDate = sdf.parse(timeStamp);
    //invoking toString() method which has its fixed format output
    System.out.println(parsedDate.toString());

现在使用

    System.out.println(sdf.format(parsedDate));