java - 参数太少。预期 1 个错误 - 使用 MS Access 的 DateDiff 函数时

Question

SELECT DateDiff("n", LastDate, Now()) as datediffs FROM UserLog WHERE ID = 1

当我从查询设计 View (MS Access) 执行此查询时。这让我在几分钟内就变得不同了，就像这样:

datediffs
---------
2826

But when I execute the same query (including static value in where condition ID = 1) from servlet like this:

strSql = "SELECT DateDiff(\"n\", LastDate, Now()) as datediffs FROM UserLog WHERE ID = 1";
recset=stmt.executeQuery(strSql);

它给了我以下错误:

[Microsoft][ODBC Microsoft Access Driver] Too few parameters. Expected 1.

那我到底是怎么了？

Answer 1

上面的评论的撰写。

如果

SELECT TOP 5 id, lastdate FROM UserLog 

运行，那么您需要查看语句的各个其他部分。例如，如果数据库丢失引用，Now() 可能会导致问题。

但是，您报告

I executed SELECT DateDiff(\"n\", LastDate, '20-08-2012 5:15:10 PM') Which did not executed. When I tried this one SELECT LastDate, NOW() FROM ... it was executed successfully. So I suspect the problem is with Datediff() function. (–- @hims056, OP)

这很奇怪，因为 DateDiff 通常不能在 MS Access 之外工作。但是，我注意到Oracle Bugs中报告了此问题。 。在评论中，有人提到，在他或她的案例中，问题是列名错误，因此可以使用 ACE 而不是 Jet 进行连接。或者，正如您所说，“在几分钟内从 Java 获取 datediff”。