我正在尝试用 Java 创建一个简单的 HTTP Web 服务器。我只是一步一步地进行,所以它非常简单。我试图做到这一点,以便我可以从客户端读取简单的输入,并在它们都连接时从服务器输出任何内容。
在网站上搜索教程后,这就是我到目前为止所做的:
public class Server
{
public static void main(String[] args) throws Exception
{
boolean listening = true;
ServerSocket server = null;
int port = 2222;
try
{
System.out.println("Server binding to port " + port);
server = new ServerSocket(port);
}
catch(Exception e)
{
System.out.println("Error: " + e);
System.exit(1);
}
System.out.println("Server successfully binded to port " + port);
while(listening)
{
System.out.println("Attempting to connect to client");
Socket client = server.accept();
System.out.println("Successfully connected to client");
new ServerThread(client).start() ;
}
server.close();
}
}
public class ServerThread extends Thread
{
private Socket socket = null ;
public ServerThread(Socket s)
{
this.socket = s ;
}
public void run()
{
InputStream in = socket.getInputStream() ;
OutputStream out = socket.getOutputStream() ;
byte [] message, reply;
while((in.read(message))
{
out.write(reply) ;
}
in.close() ;
out.close() ;
socket.close() ;
}
}
它会绑定(bind),然后在尝试连接到客户端后挂起。这是因为我不确定你在 ServerThread 的 while 循环中做了什么,以及你对消息和回复变量做了什么 >_< 我已经很长时间没有做 Java 了,所以放轻松吧!
最佳答案
我只是将这种服务器用作“好奇心”,只是为了学习新东西,因为你正在重新发明轮子,安全原因等等......我只需要使用它一次,因为我必须与服务器进行通信使用 JSON 代码,无法安装服务器。 此代码需要更多工作,例如我们为每个请求创建一个新线程,这是一个更好的 RCF HTTP 实现,但它适用于普通浏览器。
我希望这会有所帮助。
import java.io.BufferedReader;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.net.ServerSocket;
import java.net.Socket;
public class MiniPbxManServer extends Thread {
private final int PORT = 2222;
public static void main(String[] args) {
MiniPbxManServer gtp = new MiniPbxManServer();
gtp.start();
}
public void run() {
try {
ServerSocket server = new ServerSocket(PORT);
System.out.println("MiniServer active "+PORT);
boolean shudown = true;
while (shudown) {
Socket socket = server.accept();
InputStream is = socket.getInputStream();
PrintWriter out = new PrintWriter(socket.getOutputStream());
BufferedReader in = new BufferedReader(new InputStreamReader(is));
String line;
line = in.readLine();
String auxLine = line;
line = "";
// looks for post data
int postDataI = -1;
while ((line = in.readLine()) != null && (line.length() != 0)) {
System.out.println(line);
if (line.indexOf("Content-Length:") > -1) {
postDataI = new Integer(line
.substring(
line.indexOf("Content-Length:") + 16,
line.length())).intValue();
}
}
String postData = "";
for (int i = 0; i < postDataI; i++) {
int intParser = in.read();
postData += (char) intParser;
}
out.println("HTTP/1.0 200 OK");
out.println("Content-Type: text/html; charset=utf-8");
out.println("Server: MINISERVER");
// this blank line signals the end of the headers
out.println("");
// Send the HTML page
out.println("<H1>Welcome to the Mini PbxMan server</H1>");
out.println("<H2>GET->"+auxLine+ "</H2>");
out.println("<H2>Post->"+postData+ "</H2>");
out.println("<form name=\"input\" action=\"imback\" method=\"post\">");
out.println("Username: <input type=\"text\" name=\"user\"><input type=\"submit\" value=\"Submit\"></form>");
//if your get parameter contains shutdown it will shutdown
if(auxLine.indexOf("?shutdown")>-1){
shudown = false;
}
out.close();
socket.close();
}
server.close();
} catch (Exception e) {
e.printStackTrace();
}
}
}
网址:本地主机:2222/随便
关于java - 如何在 Java 中的简单 HTTP Web 服务器中读取客户端的输入?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/12770052/