方法 testPerfect 应该从 getPerfect 接收一个数字，对数字进行分解并将数字放入数组中。
我目前有数组打印，但全为零。关于将数字的因子放入数组中的任何建议？
public class aermel_Perfect
{
public static void main ( String args [] )
{
int gN;
int gP = getPerfect();
int [] array = new int[100];
//int printFactors;
System.out.println(Arrays.toString(array));
}
public static int getNum() //Get amount of numbers to check
{
Scanner input = new Scanner ( System.in );
System.out.print( "How many numbers would you like to test? " );
int count = input.nextInt();
int perfect = 1;
boolean vN = validateNum(count, perfect);
while(!vN)
{
System.out.print (" How many numbers would you like to test? ");
count = input.nextInt();
vN = validateNum(count, perfect);
}
return count;
}
public static boolean validateNum( int count, int perfect ) //Check if number is valid
{
if (( count <= 0) || ( perfect <= 0))
{
System.out.print( "Non-positive numbers are not allowed.\n");
}
else
{
return true;
}
return false;
}
public static int getPerfect() //Gets the numbers to test
{
Scanner input = new Scanner ( System.in );
int perfect = -1;
int count = getNum();
System.out.print("Please enter a perfect number: " );
perfect = input.nextInt();
boolean vN = validateNum(perfect, count);
while (!vN)
{
System.out.print("Please enter a perfect number: ");
perfect = input.nextInt();
vN=validateNum(perfect, count);
}
return perfect;
}
public static int[] testPerfect( int perfect, int[] array )
{
testPerfect(perfect, array);
int limit = (int) Math.ceil(Math.sqrt(perfect));
int index = 0;
for ( int i = 1; i <=limit; i++)
{
array[index++] = i;
perfect /= i;
}
array[index] = perfect;
return array;
}
}
最佳答案
也许是这样的？
首先，您需要使用从 getPerfect() 接收的 gP 和 array 从主函数调用 testPerfect() > 作为参数。
其次，您需要删除调用 testPerfect()，它是方法 testPerfect() 的第一行，否则这将导致无限递归调用。
public class aermel_Perfect
{
public static void main ( String args [] )
{
int gN;
int gP = getPerfect();
int [] array = new int[100];
array=testPerfect(gP,array);
//int printFactors;
System.out.println(Arrays.toString(array));
}
public static int getNum() //Get amount of numbers to check
{
Scanner input = new Scanner ( System.in );
System.out.print( "How many numbers would you like to test? " );
int count = input.nextInt();
int perfect = 1;
boolean vN = validateNum(count, perfect);
while(!vN)
{
System.out.print (" How many numbers would you like to test? ");
count = input.nextInt();
vN = validateNum(count, perfect);
}
return count;
}
public static boolean validateNum( int count, int perfect ) //Check if number is valid
{
if (( count <= 0) || ( perfect <= 0))
{
System.out.print( "Non-positive numbers are not allowed.\n");
}
else
{
return true;
}
return false;
}
public static int getPerfect() //Gets the numbers to test
{
Scanner input = new Scanner ( System.in );
int perfect = -1;
int count = getNum();
System.out.print("Please enter a perfect number: " );
perfect = input.nextInt();
boolean vN = validateNum(perfect, count);
while (!vN)
{
System.out.print("Please enter a perfect number: ");
perfect = input.nextInt();
vN=validateNum(perfect, count);
}
return perfect;
}
public static int[] testPerfect( int perfect, int[] array )
{
//testPerfect(perfect, array);
int limit = (int) Math.ceil(Math.sqrt(perfect));
int index = 0;
for ( int i = 1; i <=limit; i++)
{
array[index++] = i;
perfect /= i;
}
array[index] = perfect;
return array;
}
}
关于java - 将数字因式分解放入数组中，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/13449509/