java - Java 中的顺序字符串搜索

Question

你好再次堆栈溢出..呃， 我创建了这段代码来顺序搜索数组以查找值，在本例中是名称。但是我无法让它工作，它找不到我输入的名称，并且始终返回值 -1。

当我将所有类型更改为 INT 并对年龄数组进行搜索时，它起作用了，所以它可能与字符串类型有关？有人可以帮我吗？

public static void main(String[] args) {

    String[] name = {"John", "bert", "Elle", "beth"};
    String[] sex = {"Male", "Male", "female", "female"};
    int[] age = {18, 25, 22, 36};
    int found;

    Scanner keyboard = new Scanner(System.in);
    System.out.println("Enter name to search: ");

    String searchName = keyboard.next();

    found = searchNames(name, searchName);

    if(found == -1)
        System.out.println("Error, not found: " + found);
    else
        System.out.println("Found At: " + found);

}

private static int searchNames(String[] name, String searchName) {

    int i = 0, foundAt = -1;
    boolean found = false;

    while (!found && i < name.length)
    {
        if (name[i] == searchName)
        {
            found = true;
            foundAt = i;
        }
        i++;
    }
    return foundAt;
}

Answer 1

此功能很快就会关闭，但请使用 .equals() 来比较字符串。