java - 方法超时

Question

我的程序如下所示

1. 主程序(线程 1)
2. 创建多个简单的 java 线程(Thead 1.1、1.2...)
3. 在每个线程(1.1 或 1.2..)中，我正在进行一些处理，同时调用一个方法，该方法是 有时没有响应(CORBA 调用)。我想定义计时器 这个方法和线程(1.1或1.2，无论谁调用)应该在那里等待，直到我得到响应或计时器过期。

我编写了以下示例程序。我认为这不是正确的做法。有没有更好的方法？在此 prg 中，我不确定何时调用中断方法。

public class MethodTimeout implements Runnable{

/**
 * @param args
 */

public Thread t1 = null;
public int threadnum = 0;
public static void main(String[] args) {


    for (int i=0; i<3; i++){
        MethodTimeout mt  =new MethodTimeout();
        Thread t = new Thread(mt,"thread "+(i+1));
        mt.t1 = t;
        mt.threadnum = (i+1); 
        t.start();
    }

    System.out.println("stmt after execution");
}

public Object testTimeout(){
    long startTime = System.currentTimeMillis();
    try {

        System.out.println("in side method start "+t1.getName()+" start time"+startTime);

        Thread.sleep(5000);
    } catch (InterruptedException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
    long endtime = System.currentTimeMillis();
    System.out.println("in side method end "+t1.getName()+" total time"+(endtime-startTime) );
    return null;
}


@Override
public void run() {

    Thread timeout  = new Thread (){
        public void run() {
            testTimeout();
        };
    };
    timeout.start();

    try {
        Thread.sleep(2000);
        timeout.interrupt();
        Thread.sleep(2000);
    } catch (InterruptedException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }       
    System.out.println(t1.getName() + " is ending");
}

}

Answer 1

这听起来很像您应该实现 Callable。 这只是一个例子

 import java.util.concurrent.Callable;
 import java.util.concurrent.ExecutorService;
 import java.util.concurrent.Executors;
 import java.util.concurrent.Future;
 import java.util.concurrent.TimeUnit;
 import java.util.concurrent.TimeoutException;

 public class Test {    
     public static void main(String[] args) throws Exception {
         ExecutorService service = Executors.newFixedThreadPool(2);
         Future<String> futureResult = service.submit(new MyCall());
             try{
                 String result = futureResult.get(20, TimeUnit.MILLISECONDS);
             } catch(TimeoutException timeout){
                  System.out.println("Timeout");
                  service.shutdownNow();
             }
   }

   static class MyCall implements Callable<String> {
        @Override
        public String call() throws Exception {
             try{
                  //Simulate some corba work
                  Thread.sleep(1000);
             }catch(InterruptedException e){
                  Thread.currentThread().interrupt();
                  System.out.println("Shutting down the task!");
             }
                 return "The result";
        }
    }
}